问题
this refers to a question asked by someone else previously previous question
my question is how do I adapt this solution so that before any function/script is ran the name and value fields are stripped of any additional + and updated so no additional + remain.
For e.g.
Name Value
A+B+C+ 1+2+3+
A++B 1++2
this should be updated to
Name Value
A+B+C 1+2+3
A+B 1+2
once this update has taken place, I can run the solution provided in the previous question.
Thanks
回答1:
You need to replace ++ with + and to remove the + at the end of the string.
/* sample data */
with input(Name, Value) as (
select 'A+B+C+' ,'1+2+3+' from dual union all
select 'A++B' ,'1++2' from dual
)
/* query */
select trim('+' from regexp_replace(name, '\+{2,}', '+') ) as name,
trim('+' from regexp_replace(value, '\+{2,}', '+') ) as value
from input
If you need to update a table, you may need:
update yourTable
set name = trim('+' from regexp_replace(name, '\+{2,}', '+') ),
value= trim('+' from regexp_replace(value, '\+{2,}', '+') )
In a more compact way, without the external trim ( assuming you have no leading +):
/* sample data */
with input(Name, Value) as (
select 'A+B+C+' ,'1+2+3+' from dual union all
select 'A++B+++C+' ,'1++2+++3+' from dual union all
select 'A+B' ,'1+2' from dual
)
/* query */
select regexp_replace(name, '(\+)+(\+|$)', '\2') as name,
regexp_replace(value, '(\+)+(\+|$)', '\2') as value
from input
回答2:
You could use something on the lines of:
Select substr('1+2+3+', 0, length('1+2+3+')-1) from dual ;
Select replace('1++2', '++', '+') from dual;
I'm assuming you have the output already present in a variable you can play with.
EDIT: Here's a function that can solve the problem (You can call this function in your select clauses thereby solving the problem):
CREATE OR REPLACE Function ReplaceChars
( name_in IN varchar2 )
RETURN varchar2
IS
changed_string varchar2(20) ;
BEGIN
changed_string:=replace(name_in, '++', '+') ;
CASE WHEN substr(changed_string, -1) in ('+')
then
changed_string:=substr(changed_string,0, length(changed_string) - 1) ;
else changed_string:=changed_string ;
end CASE ;
RETURN changed_string;
END;
回答3:
You can use the below:
LTRIM(RTRIM (REGEXP_REPLACE (column_name, '\+{2,}', '+'), '+'),'+')
Eg:
SELECT LTRIM(RTRIM (REGEXP_REPLACE ('+A+++B+C+++D++', '\+{2,}', '+'), '+'),'+') VALUE
FROM DUAL;
returns output: A+B+C+D
回答4:
if youre working with ssms, GIVE IT A GO:::
UPDATE tablename
SET colname=
CASE colname WHEN LIKE '%++%' THEN
WHILE colname LIKE '%++%'
(REPLACE(colname,++,+))
END LOOP
WHEN LIKE '%+' THEN
SUBSTR(colname, 1, LENGTH(colname)-1)
WHEN LIKE '+%' THEN
SUBSTR(colname, 2, LENGTH(colname))
ELSE
colname
END
来源:https://stackoverflow.com/questions/44365517/remove-extra-from-text-sql