问题
Suppose I have an this rdd:
val r = sc.parallelize(Array(1,4,2,3))
What I want to do is create a mapping. e.g:
r.map(val => val + func(all other elements in r)).
Is this even possible?
回答1:
It's very likely that you will get an exception, e.g. bellow.
rdd = sc.parallelize(range(100))
rdd = rdd.map(lambda x: x + sum(rdd.collect()))
i.e. you are trying to broadcast the RDD therefore.
Exception: It appears that you are attempting to broadcast an RDD or reference an RDD from an action or transformation. RDD transformations and actions can only be invoked by the driver, not inside of other transformations; for example, rdd1.map(lambda x: rdd2.values.count() * x) is invalid because the values transformation and count action cannot be performed inside of the rdd1.map transformation. For more information, see SPARK-5063.
To achieve this you would have to do something like this:
res = sc.broadcast(rdd.reduce(lambda a,b: a + b))
rdd = rdd.map(lambda x: x + res.value)
回答2:
Spark already supports Gradient Descent. Maybe you can take a look in how they implemented it.
回答3:
I don't know if there is a more efficient alternative, but I would first create some structure like:
rdd = sc.parallelize([ (1, [4,2,3]), (4, [1,2,3]), (2, [1,4,3]), (3, [1,4,2]));
rdd = rdd.map(lambda (x,y) => x + func(y));
来源：https://stackoverflow.com/questions/34337528/spark-mapping-elements-of-an-rdd-using-other-elements-from-the-same-rdd