问题
Can someone please explain this behavior?
In[11]: (1, 2) in [(True, 2)]
Out[11]: True
In[12]: (1, 2) in [(True, True)]
Out[12]: False
In[13]: (1, 2) in [(True, False)]
Out[13]: False
In[14]: ("1", 2) in [(True, 2)]
Out[14]: False
It feels like a bug--whenever I check if a tuple is in a list of tuples, the integer 1 is always equal to True. I don't want to report it to the Python bug tracker if it can be explained.
回答1:
It's something of an implementation detail of True, see Is False == 0 and True == 1 in Python an implementation detail or is it guaranteed by the language? for a discussion.
回答2:
The "trick" here I suppose is that 1 == True and 0 == False both evaluate to True.
Your lines 11, 12 and 13 imply that all truthy values should be equal. If that were the case though, 1 == 2 would evaluate to True which would clearly be a bug.
来源：https://stackoverflow.com/questions/33586081/python-tuple-comparison-odd-behavior