Upload File in Object

问题

What am I doing wrong?

fileUpload.cfm

<cfcomponent name="fileAttachment" hint="This is the File Attachment Object">

    <cffunction name="uploadFile" access="public" output="no" returntype="string">
        <cfargument name="fileToUpload" type="string" required="no">
        <cfargument name="pDsn" required="no" type="string">
        <cfset var cffile = "">
        <cffile action="upload" destination="D:\apache\htdocs\abc\uploads" filefield="#ARGUMENTS.fileToUpload#" nameconflict="makeunique">
        <cfreturn cffile.clientFile />
    </cffunction>

</cfcomponent>

test_fileUpload.cfm

<form action="fileUpload.cfm" enctype="multipart/form-data" method="post">
    <input type="file" name="fileToUpload"><br/>
    <input type="submit">
</form>

回答1:

This line:

<cffile action="upload" destination="D:\apache\htdocs\abc\uploads" filefield="#ARGUMENTS.fileToUpload#" nameconflict="makeunique">

The filefield attribute wants the name of the form field that will hold the uploaded file. You're on the right track, but unfortunately, that's not what the value of #ARGUMENTS.fileToUpload# is, presently--based on your construction, it holds a reference to the actual file itself.

Add a new hidden field to your form:

<input type="hidden" name="nameOfField" value="fileToUpload">

Then, pass FORM.nameOfField to your uploadFile() method as the first parameter. CFFILE will take care of the rest.

回答2:

Well, I found lots of issue with this code.

1. fileupload.cfm should be component file fileupload.cfc as you are writing component in it.
2. As you are going to call directly upload method from form call access type must be REMOTE.
3. action page should change to fileupload.cfc?method=uploadFile
4. if you define cffile as local variable of component then you have to specify result="cffile" attribute in cffile tag.
5. filefield attribute take the name of form field not its value so just remove ## tag and just use fileToUpload.

Below is correct code. fileupload.cfc

<cffunction name="uploadFile" access="remote" output="no" returntype="string">
    <cfargument name="fileToUpload" type="string" required="no">
    <cfargument name="pDsn" required="no" type="string">
    <cfset var cffile = "">
    <cffile action="upload" destination="D:\apache\htdocs\abc\uploads" filefield="fileToUpload" result="cffile" nameconflict="makeunique">
    <cfreturn cffile.clientFile />
</cffunction>

</cfcomponent>

test_fileupload.cfm

`<form action="fileupload.cfc?method=uploadFile" enctype="multipart/form-data" method="post">
   <input type="file" name="fileToUpload"><br/>
   <input type="submit">   </form>`

来源：https://stackoverflow.com/questions/8733270/upload-file-in-object