问题
i have a csv file from 5 year malware data collected there are 2 columns the dates and the ips every date have 1 or more ips example
1/5/2013 12.234.123
1/5/2013 45.123.566
1/5/2013 100.546.12
1/6/2013 42.153.756
3/4/2014 75.356.258 etc... (every day for 5 years)
now i am trying to get the percentage difference between every month example:
November 2014 - 10%
December 2014 - 15%
i tried to put the percentage on y axis and in x2 axis but im getting some crazy results i am new to gnuplot and im still learning it here is the code i have right now:
set title 'Results Per Month'
set xlabel 'Date'
set ylabel 'Percentage'
set terminal png size 2800,900
set datafile sep ','
set xdata time
set timefmt '%Y/%m/%d'
set xrange['2009/3/22':'2014/12/02']
set xtics 30*24*60*60
set format x '%Y/%m'
set autoscale x2fix
set x2tics
set x2range[0:*]
set format x2 "%g %%"
set xtics nomirror rotate by -90
set grid ytics xtics
set ytics 10
set yrange [0:*]
set term png
set output 'file.png'
plot 'export.csv' using (timecolumn(1) - (tm_mday(timecolumn(1))-1)*24*60*60):(1) smooth frequency w lp pt 7 ps 2 notitle, \
'' using (($1-$2)/$1*100):x2ticlabels(2) axes x2y1 with points ps 2 lw 2
回答1:
I would suggest you to use some external script for such kind of preprocessing (you can also do this on-the-fly). Yes, you can do this in gnuplot in two steps, but can become quite complicated and requires some more profound knowledge of gnuplot.
Here is a working script, but I won't go into detail about the many different aspects of the actual implementation:
set xdata time
set timefmt '%Y/%m/%d'
set datafile separator ','
set table 'temporaryfile.dat'
set format x '%Y/%m/%d'
plot 'export.csv' using (timecolumn(1) - (tm_mday(timecolumn(1))-1)*24*60*60):(1) smooth frequency
unset table
set y2tics
set ytics nomirror
set timefmt '"%Y/%m/%d"'
set format x '%b %Y'
set xtics rotate by 90 right
set datafile separator white
set yrange[0:*]
x0=x1=0
plot 'temporaryfile.dat' using 1:(strcol(3) eq "i" ? $2 : 1/0) w lp pt 7 ps 2 title 'IP count', \
'' using 1:(x1=x0, x0=$2, strcol(3) eq "i" ? ($0 == 0 || x0 == 0 ? 0 : (x0-x1)/x0 * 100.0) : 1/0) axes x1y2 w lp title 'percentual change'
Basically, first you plot the result data of smooth frequency into a second data file. Then you can plot this, and to the calculations for the percentages.
Please note, that I used a timeformat which corresponds to your test data (and the data of your previous question), which doesn't correspond with what you have in your script! Please pay attention to this.
Also note, that the timefmt before the actual plot must be extended by quote signs which are written around the dates in tmp.dat.
Finally, the strcol(3) eq 'i' is necessary to circumvent a gnuplot bug, which causes a last line to be written with invalid data.
来源：https://stackoverflow.com/questions/27531782/gnuplot-percentage-difference-between-2-months