split string based on character position in ORACLE 11g SQL

问题

I'm using oracle 11g sql developer

I have a varchar2 column with dates as 0523 (mmDD).

I want to convert them to a date column and have them look like 23-05 (dd-mm)..

Any ideas?

回答1:

Well, you can do string operations directly to get the format you want:

substring(c, 3, 2)||'-'||substring(c, 1, 2)

To convert to a date, you can use:

to_date('2012'||c, 'YYYYMMDD')

To convert a date back to the form you want:

to_char(<date>, 'DD-MM')

来源：https://stackoverflow.com/questions/11231161/split-string-based-on-character-position-in-oracle-11g-sql