List difference (omit one list from other list) in NetLogo

问题

In case we want to omit one list from other list in Netlogo , how we should write the code? For example, first list is [1 2 3 4 5] And second list is [4 5] In this case what code should be written to remove list 2 from list 1 so as to having a new list comprises of 1, 2 and 3?

回答1:

Code:

to-report difference [l1 l2]
  report filter [not member? ? l2] l1
end

Sample runs:

observer> show difference [1 2 3 4 5] [4 5]
observer: [1 2 3]
observer> show difference [1 2 3 6] [1 2 3 4 5]
observer: [6]

来源：https://stackoverflow.com/questions/30895592/list-difference-omit-one-list-from-other-list-in-netlogo