问题
I am getting an error indicating the wrong number of arguments when I run the following query:
SELECT
population_postcodes.*,
target_postcodes.*,
SQR( EXP(population_postcodes.longitude- target_postcodes.longitude, 2) + EXP(population_postcodes.latitude-target_postcodes.latitude, 2) ) as distance
FROM population_postcodes INNER JOIN target_postcodes on Population_postcodes.Population_postcode = Target_postcodes.Target_postcode;
Could anyone please suggest how I can fix this?
I have also tried the following code:
SELECT Population_postcodes.*, Target_postcodes.*
FROM population_postcodes
INNER JOIN target_postcodes
ON Population_postcodes.Population_postcode = Target_postcodes.Target_postcode
SQR( (population_postcodes.longitude- target_postcodes.longitude)^2 + (population_postcodes.latitude-target_postcodes.latitude)^2 ) as distance;
And this code:
SELECT Population_postcodes.*, Target_postcodes.*, SQR( (population_postcodes.longitude- target_postcodes.longitude)^2 + (population_postcodes.latitude-target_postcodes.latitude)^2 ) as distance
FROM population_postcodes
INNER JOIN target_postcodes
ON Population_postcodes.Population_postcode = Target_postcodes.Target_postcode;
回答1:
Exp needs one parameter, you give two.
Old: EXP(population_postcodes.longitude- target_postcodes.longitude, 2)
New: (population_postcodes.longitude- target_postcodes.longitude)*(population_postcodes.longitude- target_postcodes.longitude)
回答2:
Try replacing...
EXP(<expression>, 2)
...to...
<expression>^2
In Access, the EXP function returns e (the base of natural logarithms) raised to a power. To raise an expression to a power, use the ^ operator.
In your case, be careful to put brackets around the expression, for example...
(population_postcodes.longitude- target_postcodes.longitude)^2
...to force the power to be applied last. By default, the ^ operator is evaluated before the - operator.
来源：https://stackoverflow.com/questions/20996713/wrong-number-of-arguments-sql-msaccess