问题
I'm attempting to use the build in Functions in OrientDB studio to group Workstations that aren't in use by a Person. The query to get these vertices works fine but I'm trying to avoid Traverse as it is very slow - too slow to be used in production. Instead of iterating through each free station and grouping it together with all it's neighbours, keeping each grouped 'named' with the smallest @rid in the set.
var groups = {}; //The list of groups of workpoints. The key is the lowest RID in the group
var mappedDesks = {}; //Every desk's RID is in this object with it's matching value being the group name they're in
//Get all Workpoints that don't have a Locale CURRENTLY_LOCATED_ON them
var freeDesks = db.query("SELECT FROM Workpoint WHERE @rid NOT IN (SELECT @rid FROM (SELECT EXPAND(OUT('CURRENTLY_LOCATED_ON').OUT('LOCATED_ON')) FROM Person) WHERE @class = 'Workpoint')");
//Iterate through all vacant Workpoints
for (var j=0; j < freeDesks.length; j++){
var baseNodeRid = freeDesks[j].getRecord().getIdentity().toString(); // The RID of the Workpoint
var baseNodeNumber = parseFloat(baseNodeRid.replace("#", "").replace(":",".")); // The RID converted to a number for comparisons. The lower RID takes precedence
var baseSanitized = baseNodeRid.replace(":","-") // Keys cannot contain colon so they are replaced with a dash
if (freeDesks[j].getRecord().field("out_NEIGHBOUR_OF") == null ) {
// Desks without neighbours can be put in a group on their own
groups[baseSanitized] = new Array();
groups[baseSanitized].push(baseNodeRid);
mappedDesks[baseSanitized] = baseSanitized;
} else {
//Iterate over all the desk's neighbours
for (var n = 0; n < freeDesks[j].getRecord().field("out_NEIGHBOUR_OF").length; n++){
//Convert the neighbour's RID to a number too
var nSanitized = n.replace(":","-");
if (parseFloat(n.replace("#", "").replace(":",".")) > baseNodeNumber ){
//The neighbour's node group is larger than the current one. This needs to be merged into the group with the smaller rid
//Move the desks from the neighbour's group into the base's group. If it has none then do nothing
var nGroup = groups[mappedDesks[nSanitized]]
if ( nGroup != null) {
groups[baseSanitized] = groups[baseSanitized].concat(nGroup);
//Change the mapping of each moved desk to the base's
for (var g = 0; g < nGroup.length; g++){
mappedDesks[nGroup[g]] = baseSanitized;
}
}
//Delete the reference to the old group
delete groups[mappedDesks[nSanitized]];
//Update the mappings for the desks dealt with
mappedDesks[nSanitized] = baseSanitized;
mappedDesks[baseSanitized] = baseSanitized;
} else {
// The neighbour is lower than the current desk so the desk should be merged into the neighbour's group
mappedDesks[baseSanitized] = nSanitized;
groups[nSanitized].push(baseNodeRid);
}
}
}
}
return groups;
My problem comes from accessing a vertex's neighbours. It correctly determines whether there are neighbours in the if statement return freeDesks[j].getRecord().field("out_NEIGHBOUR_OF")
but I want to be able to get each neighbour's @rid so I can sort the @rids into groups.
freeDesks[j].getRecord().field("out_NEIGHBOUR_OF")
returns the edge record but I dont seem to be able to get the "in" or "out" fields using the field() method (not found on this object) or accessing it as an array [].
[
{
"@type": "d",
"@rid": "#34:18176",
"@version": 6,
"@class": "NEIGHBOUR_OF",
"out": "#16:13",
"in": "#16:1408",
"@fieldTypes": "out=x,in=x"
}
]
Can you help be get a list/array of the neighbour @rids so I can iterate over them with the rest of the code?
Cheers!
回答1:
A simpler example to understand what you can do:
create class Person extends V
create class IsNeighbour extends E
create vertex Person set name = 'P1' // 12:0
create vertex Person set name = 'P2' // 12:1
create vertex Person set name = 'P3' // 12:2
create edge IsNeighbour from #12:0 to #12:1
create edge IsNeighbour from #12:0 to #12:2
Define this Javascript Function:
var gdb = orient.getGraphNoTx();
var v = gdb.command("sql", "select from " + personRID);
var neighbours = v[0].getRecord().field("out_IsNeighbour").iterator();
var result = [];
while(neighbours.hasNext()){
var neighbour = neighbours.next();
result.push(neighbour.field("in"));
}
return result;
like this:

And then you can:
select getNeighbours("#12:0")
来源:https://stackoverflow.com/questions/30476862/accessing-connected-vertices-in-orientdb-javascript-functions