问题
I currently have the following datatable to display my list of contacts from the database. Each row, I have also insert a "Edit" & "Delete" button and have the data-id="<?=$row['id']?>" passed for the jQuery to handle when the button is clicked. When the button is clicked, through ajax, I will get the data from getcontact.php and set it to the respective input in the modal form, however the data does not seem to be displaying in the form values. May I know where did I go wrong?
tables.php
<table width="100%" class="display table table-striped table-bordered table-hover" id="contactsTable">
<thead>
<tr>
<th>ID</th>
<th>Name</th>
<th>Company</th>
<th>Position</th>
<th>Phone</th>
<th>Email</th>
<th>Gender</th>
<th>Date Registered</th>
<th>Edit</th>
<th>Delete</th>
</tr>
</thead>
<tbody>
<?php
while($row = mysqli_fetch_array($result)){
?>
<tr>
<td><?=$row['id']?></td>
<td><?=$row['name']?></td>
<td><?=$row['company']?></td>
<td><?=$row['position']?></td>
<td><?=$row['phone']?></td>
<td><?=$row['email']?></td>
<td><?=$row['gender']?></td>
<td><?=$row['dateregistered']?></td>
<td>
<!-- Edit Button trigger modal -->
<button id="editButton" type="button" class="btn btn-primary" datatoggle="modal" data-target="#editModal" data-id="<?=$row['id']?>">
Edit
</button>
</td>
<td>
<!-- Delete Button trigger modal -->
<button type="button" class="btn btn-primary" data-toggle="modal" data-target="#deleteModal" data-id="<?=$row['id']?>">
Delete
</button>
</td>
</tr>
<?php
}
?>
</tbody>
</table>
Modal (in the same page as tables.php)
<!-- Edit Contact Modal -->
<div class="modal fade" id="editModal" tabindex="-1" role="dialog" aria labelledby="myModalLabel">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">×</span></button>
<h4 class="modal-title" id="myModalLabel">Edit Contact</h4>
</div>
<div class="modal-body">
<form class="form-horizontal" method="POST" id="editForm" role="form">
<div class="form-group animated fadeIn">
<label for="nameInput" class="col-sm-2 control-label">Name</label>
<div class="col-sm-10">
<input type="name" name="name" class="form-control" id="nameInput" placeholder="Name" required>
</div>
</div>
<div class="form-group animated fadeIn">
<label for="companyInput" class="col-sm-2 control-label">Company</label>
<div class="col-sm-10">
<input type="company" name="company" class="form-control" id="companyInput" placeholder="Company" required>
</div>
</div>
<div class="form-group animated fadeIn">
<label for="posInput" class="col-sm-2 control-label">Position</label>
<div class="col-sm-10">
<input type="position" name="position" class="form-control" id="posInput" placeholder="Position/Job Title">
</div>
</div>
<div class="form-group animated fadeIn">
<label for="contactInput" class="col-sm-2 control-label">Contact Number</label>
<div class="col-sm-10">
<input type="number" name="contact" class="form-control" id="contactInput" placeholder="Office/Mobile Number" data-error="Please enter a valid mobile number" required>
</div>
</div>
<div class="form-group animated fadeIn">
<label for="emailInput" class="col-sm-2 control-label">Email</label>
<div class="col-sm-10">
<input type="email" name="email" class="form-control" id="emailInput" placeholder="Email Address">
</div>
</div>
<div class="form-group animated fadeIn">
<label for="genderInput" class="col-sm-2 control-label">Gender</label>
<div class="col-sm-10">
<input type="gender" name="gender" class="form-control" id="genderInput" placeholder="Male/Female">
</div>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<button id="editContact" type="button" class="btn btn-primary">Save</button>
</div>
</form>
</div>
jQuery
$("#editButton").click(function(e){
e.preventDefault();
var uid = $(this).data('id'); // get id of clicked row
$.ajax({
url: 'getcontact.php',
type: 'POST',
data: 'id='+uid,
dataType: 'json',
success: function(response){
$("#nameInput").val(result[0]);
$("#companyInput").val(result[1]);
$("#posInput").val(result[2]);
$("#contactInput").val(result[3]);
$("#emailInput").val(result[4]);
$("#genderInput").val(result[5]);
}
});
});
getcontact.php
<?php
include("dbconnect.php");
$id = $_POST['id'];
$result = mysqli_query($link, "SELECT * FROM businesscontact WHERE id=$id");
$rows = array();
while($row = mysqli_fetch_array($result)){
$rows[] = $row['*'];
}
echo json_encode($rows);
?>
回答1:
1 - you are sending a encoded json from your php file and use it directly from you javascript code which is invalid so to speak,
2 - you are sending the data object to php using ajax wrongly, it should be as follows instead data: {id: uid},
3 - you are declare the wrong data-id , it should be as follows: var uid = $(this).attr('data-id');
you need to decode your json response as follows:
var uid = $(this).attr('data-id');
$.ajax({
url: 'getcontact.php',
method: 'POST',
data: {id: uid},
success: function(response){
var result = JSON && JSON.parse(response) || $.parseJSON(response);
...
// rest of your code
...
Update
and you have an issue in this part:
while($row = mysqli_fetch_array($result)){
$rows[] = $row['*'];
}
to add the whole array you need to do as follows:
while($row = mysqli_fetch_array($result)){
$rows[] = $row;
}
来源：https://stackoverflow.com/questions/42760194/displaying-php-echo-row-data-into-bootstrap-modal-form