问题
I am working with A* algorithm. I have a 2D grid, with some obstacles, and given the starting and final position, I find the shortest path between them.
Here's my pseudocode
while(queueNotEmpty){
removeFromPQ;
if(removed == destination)
found;
insertAllNeighbours;
}
Remove and insert are the function on priority queue(Heap), and is O(log(n)) time.
Considering the dimension of grid as N*N. How do I calculate the running time. i.e how many times will this loop execute? Is there any measure?
回答1:
Runtime of standard A* is exponential in the length of the solution (worst-case).
If you're searching on a grid of n*n
, and you use graph-search, the search will visit each node at most once; so it's O(n*n)
. But the found solution will only be optimal if the used heuristic is monotone (in addition to being admissible).
There are also conditions for polynomial runtime of standard A*.
For Graph-Search vs. Tree-Search see this answer.
来源:https://stackoverflow.com/questions/16141678/how-to-compute-the-running-time-of-a-star-algorithm