Bash: total size of file in current directory matching regular expression

问题

ls | grep -P "$1" | awk '{ x += $5 } END { print "total bytes:" x }' 

This code is returning 0 using "[0-9]" as reg expr, in current folder there are 2 files named: "1" and "6", each one with size of 138bytes.

Anyone could help me to find the problem?

回答1:

You're just missing the -l option to ls.

ls -l | grep -P "$1" | awk '{ x += $5 } END { print "total bytes:" x }' 

回答2:

du can help you with this; it has a -c flag for displaying a "grand total". It results in a final line containing the total size followed by the word total. Therefore, the following should give you the total size in bytes for your selection:

du -bc yourFilePattern | awk 'END {print $1}'

EDIT:

If something like *pattern* is not enough and you want a regex, just use:

ls | grep -P "$regex" | xargs du -bc | awk 'END {print $1}'

来源：https://stackoverflow.com/questions/14690431/bash-total-size-of-file-in-current-directory-matching-regular-expression