Access zoo or xts index

不羁岁月 提交于 2019-11-27 02:34:15

问题


I am using zoo objects, buy my question also applies to xts objects. It looks to me like it is a one column vector with an index. In my case the index is the vector of dates and the one column vector my data. All is good except that I would like to access the dates (from the index).

For example I have the following result:

ObjZoo <- structure(c(10, 20), .Dim = c(2L, 1L), index = c(14788, 14789),
                    class = "zoo", .Dimnames = list(NULL, "Data"))
unclass(ObjZoo)
#      Data
# [1,]   10
# [2,]   20
# attr(,"index")
# [1] 14788 14789

I want to get 14789 in a variable or a vector, but I'm not sure how to access it.


回答1:


From the help for ?zoo, there are two convenience methods to access the data in zoo objects:

  • coredata() returns the data in the zoo object
  • index() returns the index

For example:

x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 9, 14) - 1
x <- zoo(rnorm(5), x.Date)

index(x)
[1] "2003-02-01" "2003-02-03" "2003-02-07" "2003-02-09" "2003-02-14"

coredata(x)
[1] -1.2487943  0.8911630  1.2713133 -0.1024638  0.2989194



回答2:


In general when you see attr, this means that this data is an attribute of an object.

attributes function can be used to dump all attributes as a list, so you can access certain element with $:

attributes(ObjZoo)$index

attr gives you direct access to the attribute by its name:

attr(ObjZoo,"index")

In fact this is what index does:

> zoo:::index.zoo

function (x, ...) 
{
    attr(x, "index")
}
<environment: namespace:zoo>


来源:https://stackoverflow.com/questions/6465222/access-zoo-or-xts-index

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