Can you spawn a process in a shell script?

问题

I'm trying to get my #!/bin/sh shell script to start another application without pausing execution. That is I'm looking for a way to launch it in the background and have my shell script keep executing. I want it to work something like this:

# start daemon
start(){
success=`launch '/path/to/daemon'`
if [ $success != false ];then
echo 'daemon is now running'
fi

I'm also new to shell scripting so will the above (if launch existed) get the return of launch or the stdout set as $success?

I want to only use SH not BASH.

回答1:

Use '&' sign after program name to launch it in background. Putting a program in the background

回答2:

use NOHUP. http://en.wikipedia.org/wiki/Nohup and send output to log using >> mylogfilename

来源：https://stackoverflow.com/questions/7133396/can-you-spawn-a-process-in-a-shell-script