问题
I am trying to create a utility class ReadPropertyUtil.java
for reading data from property file. While my class is located under a util directory , my skyscrapper.properties
file is placed in some other directory.
But , when i try to access the properties using [ResourceBundle][1]
, i get exceptions, that bundle can't be loaded.
Below is the code on how I am reading the properties and also an image which shows my directory structure.
ReadPropertiesUtil.java
/**
* Properties file name.
*/
private static final String FILENAME = "skyscrapper";
/**
* Resource bundle.
*/
private static ResourceBundle resourceBundle = ResourceBundle.getBundle(FILENAME);
/**
* Method to read the property value.
*
* @param key
* @return
*/
public static String getProperty(final String key) {
String str = null;
if (resourceBundle != null) {
str = resourceBundle.getString(key);
LOGGER.debug("Value found: " + str + " for key: " + key);
} else {
LOGGER.debug("Properties file was not loaded correctly!!");
}
return str;
}
Directory Structure

This line is giving the error private static ResourceBundle resourceBundle = ResourceBundle.getBundle(FILENAME);
I am unable to understand why isn't this working and what is the solution. The src
folder is already added in build path completely.
回答1:
Try with the fully qualified name for the resource:
private static final String FILENAME = "resources/skyscrapper";
回答2:
ResourceBundle doesn't load files? You need to get the files into a resource first. How about just loading into a FileInputStream then a PropertyResourceBundle
FileInputStream fis = new FileInputStream("skyscrapper.properties");
resourceBundle = new PropertyResourceBundle(fis);
Or if you need the locale specific code, something like this should work
File file = new File("skyscrapper.properties");
URL[] urls = {file.toURI().toURL()};
ClassLoader loader = new URLClassLoader(urls);
ResourceBundle rb = ResourceBundle.getBundle("skyscrapper", Locale.getDefault(), loader);
回答3:
Use the Resource like
ResourceBundle rb = ResourceBundle.getBundle("com//sudeep//internationalization//MyApp",locale);
or
ResourceBundle rb = ResourceBundle.getBundle("com.sudeep.internationalization.MyApp",locale);
Just give the qualified path .. Its working for me!!!
回答4:
You should set property file name without .properties
extension,
it works correctly for me:)
回答5:
I'd like to share my experience of using Ant in building projects, *.properties files should be copied explicitly. This is because Ant will not compile *.properties files into the build working directory by default (javac just ignore *.properties). For example:
<target name="compile" depends="init">
<javac destdir="${dst}" srcdir="${src}" debug="on" encoding="utf-8" includeantruntime="false">
<include name="com/example/**" />
<classpath refid="libs" />
</javac>
<copy todir="${dst}">
<fileset dir="${src}" includes="**/*.properties" />
</copy>
</target>
<target name="jars" depends="compile">
<jar jarfile="${app_jar}" basedir="${dst}" includes="com/example/**/*.*" />
</target>
Please notice that 'copy' section under the 'compile' target, it will replicate *.properties files into the build working directory. Without the 'copy' section the jar file will not contain the properties files, then you may encounter the java.util.MissingResourceException.
回答6:
With Eclipse and Windows:
you have to copy 2 files - xxxPROJECTxxx.properties - log4j.properties here : C:\Eclipse\CONTENER\TOMCAT\apache-tomcat-7\lib
回答7:
I have just realized that my error was caused in the naming convention of my property file. When i used xxxx.xxxx.properties i got the error:
java.util.MissingResourceException: Can't find bundle for base name 'property_file name', locale en_US
Changing it to something like xxx-xxxx.properties works like a charm. Hope i help someone!
回答8:
just right click on the project file in eclipse and in build path select "Use as source folder"...It worked for me
来源:https://stackoverflow.com/questions/20142002/java-util-missingresourceexception-cant-find-bundle-for-base-name-property-fi