How to check if a file is executable in Bash [duplicate]

问题

I am trying to build a condition that check if file has execute access bit set. I can't use grep and find.

I tried something with checking the "x" letter in the ls -l command but this is wrong in many cases.

for val in `ls $1`
do
  if [[ "`ls -l $1/$val`" -eq *w* ]]
  then
    rm $1/$val
  fi
done

Please help or give some advices!

回答1:

There is no need to parse the output of ls to see if a file is executable. Shell provides the built-in -x check for that. Using -x feature, your loop could be re-written as:

for file in "$1"/*; do
  [[ -x "$file" ]] && rm -- "$file"
done

回答2:

if [ -x "$file" ]; then
  # do something
fi

You can get many more options of file testing using man :

~]# man test
.... 
-x FILE
              FILE exists and execute (or search) permission is granted

Following should work:

 ~]# find $1 -type f | while IFS='' read -r -d '' p; 
     do 
        if [ -x "$p" ]; then 
           echo "removing $p";
           rm "$p";
        fi; 
     done

find command gets all the files (including .) in the directory given by $1. while reads each of these output, if then checks individual files for executable permission with-x.

EDIT

After some comments, here is a swifter example:

find "$1" -type f -executable -exec rm -- {} \;

来源：https://stackoverflow.com/questions/42633413/how-to-check-if-a-file-is-executable-in-bash

标签

bash