问题
Basically my question is: how do I sum relationship properties where there is a related nodes that have properties equal to Value A and Value B?
For example:
I have a simple DB has the following relationship:
(site)-[:HAS_MEMBER]->(user)-[:POSTED]->(status)-[:TAGGED_WITH]->(tag)
On [:TAGGED_WITH] I have a property called "TimeSpent". I can easily SUM up all the time spent for a particular day and user by using the following query:
MATCH (user)-[:POSTED]->(updates)-[r:TAGGED_WITH]->(tags)
WHERE user.name = "Josh Barker" AND updates.date = 20141120
RETURN tags.name, SUM(r.TimeSpent) as totalTimeSpent;
This returns to me a nice table with tags and associated time spent on each. (i.e. #Meeting 4.5). However, the question arises if I want to do some advanced searches and say "Show me all the meetings for ProjectA" (i.e. #Meeting #ProjectA). Basically, I am looking for a query that I can get all of the relationships where a single status has BOTH tags (and only if it has both). Then I can SUM that number up to get a count for how many meetings I spent in #ProjectA.
How do I do this?
回答1:
MATCH (updates)-[r:TAGGED_WITH]->(tag1 {name: 'Meeting'}),
(updates)-[r:TAGGED_WITH]->(tag2 {name: 'ProjectA'})
RETURN SUM(r.TimeSpent) as totalTimeSpent, count(updates);
This should find all updates tagged with both of those things, and sum all time spent across all of those updates.
回答2:
To create a generic solution where you may want one or more tags you could use something like this, passing in the array of tags as a parameter (and using the length of the array instead of the hard coded 2
.
MATCH (user)-[:POSTED]->(update)-[r:TAGGED_WITH]->(tag)
WHERE user.name = "Josh Barker" AND updates.date = 20141120 AND tag.name IN ['Meeting', 'ProjectA']
WITH update, SUM(r.TimeSpent) AS totalTimeSpent, COLLECT(tag) AS tags
WHERE LENGTH(tags) = 2
RETURN update, totalTtimeSpent
As long as tag.name
is indexed, this should be fast.
Edit - Remove User constraint
MATCH (update)-[r:TAGGED_WITH]->(tag)
WHERE tag.name IN ['Meeting', 'ProjectA']
WITH update, SUM(r.TimeSpent) AS totalTimeSpent, COLLECT(tag) AS tags
WHERE LENGTH(tags) = 2
RETURN update, totalTtimeSpent
来源:https://stackoverflow.com/questions/27053509/neo4j-sum-relationship-properties-where-node-properties-equal-value-a-and-value