问题
I am trying to create an Observable that will emit new object every second. So for now i am just zipping one Observable, which emits finite number of objects from a list, with interval Observable.
val list1 = mutableListOf<SomeClass1>(
SomeClass1("1", 1), SomeClass1("2", 2), SomeClass1("3", 3),
SomeClass1("4", 4), SomeClass1("5", 5), SomeClass1("6", 6),
SomeClass1("7", 7), SomeClass1("8", 8), SomeClass1("9", 9)
)
val someClass1Observable = Observable
.fromIterable(list1)
.zipWith(Observable.interval(2, TimeUnit.SECONDS),
BiFunction { item: SomeClass1, _: Long -> item })
So how to actually make this infinite, in a way that every 2 second there will be emiited new object of class SomeClass1 with some parameters?
回答1:
Here is the answer for my question, that satisfies my:
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
var counter = 0
val periodicSomeClass1 = Observable.interval(1, TimeUnit.SECONDS)
.flatMap(
{
counter++
Observable.just(SomeClass1("$counter", counter))
}
)
periodicSomeClass1.subscribe { t: SomeClass1 -> Log.v("periodicSomeClass1", t.toString()) }
}
来源:https://stackoverflow.com/questions/47366799/how-to-create-infinite-interval-observable-that-will-emit-new-object-every-time