问题
I have a quite big object to serialize to disk, like this:
if (!EngineFile.empty())
{
std::ofstream OutEngineStream(EngineFile);
if (!OutEngineStream)
{
std::cerr << "Failed to write to file \"" << EngineFile << "\"! Aborting ..." << std::endl;
return -1;
}
engine->serialize(OutEngineStream);
OutEngineStream.close();
std::cout << "\"" << EngineFile << "\" successfully wrote to disk." << std::endl;
}
The problem is, somtimes serialize
requires larger disk space than available. e.g. there is only 30M storage available but serialize
requires 200M. In this case I can normally open
the stream. During serialize
everything goes well, and close
returns nothing. The program runs well, but there is only a 30M file on the disk.
How can I get to know about this case?
回答1:
First of all, serialize
should constantly verify whether its write operations succeed and throw should they fail.
In the code you've presented you should check OutEngineStream.fail() (it covers more cases than bad
) before calling close
(because close
may also set this state). This however will still leave serialize
implemented incorrectly.
回答2:
The presented code checks for failure of opening the file.
In addition it should for failure of the write operation.
That's how to detect if the write operation failed.
回答3:
What about this:
std::fstream file;
file.exceptions( std::fstream::failbit | std::fstream::badbit );
try {
// do work
}
catch (std::fstream::failure e) {
std::cerr << "Exception opening/reading/writing/closing file\n";
}
来源:https://stackoverflow.com/questions/40056884/disk-gets-full-during-file-write-how-can-i-get-notified-about-this