Most Pythonic way to print *at most* some number of decimal places [duplicate]

Question

This question already has an answer here:

• Formatting floats in Python without trailing zeros 15 answers

I want to format a list of floating-point numbers with at most, say, 2 decimal places. But, I don't want trailing zeros, and I don't want trailing decimal points.

So, for example, 4.001 => 4, 4.797 => 4.8, 8.992 => 8.99, 13.577 => 13.58.

The simple solution is ('%.2f' % f).rstrip('.0')('%.2f' % f).rstrip('0').rstrip('.'). But, that looks rather ugly and seems fragile. Any nicer solutions, maybe with some magical format flags?

Answer 1

You need to separate the 0 and the . stripping; that way you won't ever strip away the natural 0.

Alternatively, use the format() function, but that really comes down to the same thing:

format(f, '.2f').rstrip('0').rstrip('.')

Some tests:

>>> def formatted(f): return format(f, '.2f').rstrip('0').rstrip('.')
... 
>>> formatted(0.0)
'0'
>>> formatted(4.797)
'4.8'
>>> formatted(4.001)
'4'
>>> formatted(13.577)
'13.58'
>>> formatted(0.000000000000000000001)
'0'
>>> formatted(10000000000)
'10000000000'

Answer 2

The g formatter limits the output to n significant digits, dropping trailing zeroes:

>>> "{:.3g}".format(1.234)
'1.23'
>>> "{:.3g}".format(1.2)
'1.2'
>>> "{:.3g}".format(1)
'1'

Answer 3

In general working with String[s] can be slow. However, this is another solution:

>>> from decimal import Decimal
>>> precision = Decimal('.00')
>>> Decimal('4.001').quantize(precision).normalize()
Decimal('4')
>>> Decimal('4.797').quantize(precision).normalize()
Decimal('4.8')
>>> Decimal('8.992').quantize(precision).normalize()
Decimal('8.99')
>>> Decimal('13.577').quantize(precision).normalize()
Decimal('13.58')

You may find more info here: http://docs.python.org/2/library/decimal.html