问题
When running cor() on a times series with a lot of variables, I get a table back that has a row and column for each variable, showing the correlation between them.
How can I view this table as a list from most correlated to least correlated (eliminating all NA results and results that map back to themselves (i.e. the correlation of A to A)). I would also like to count inverse (negative) results as absolute values, but still show them as negative.
So the desired output would be something like:
A,B,0.98
A,C,0.9
C,R,-0.8
T,Z,0.5
回答1:
Here's one of many ways I could think to do this. I used the reshape package because the melt()
syntax was easy for me to remember, but the melt()
command could pretty easily be done with base R commands:
require(reshape)
## set up dummy data
a <- rnorm(100)
b <- a + (rnorm(100, 0, 2))
c <- a + b + (rnorm(100)/10)
df <- data.frame(a, b, c)
c <- cor(df)
## c is the correlations matrix
## keep only the lower triangle by
## filling upper with NA
c[upper.tri(c, diag=TRUE)] <- NA
m <- melt(c)
## sort by descending absolute correlation
m <- m[order(- abs(m$value)), ]
## omit the NA values
dfOut <- na.omit(m)
## if you really want a list and not a data.frame
listOut <- split(dfOut, 1:nrow(dfOut))
回答2:
Using base R (where cors
is the correlation matrix):
up <- upper.tri(cors)
out <- data.frame(which(up, arr.ind=TRUE), cor=cors[up])
out <- out[!is.na(out$cor),]
out[order(abs(out$cor), decreasing=TRUE),]
回答3:
Replace ...
with your correlation call.
library(reshape)
x <- subset(melt(cor(...)), value != 1 | value != NA)
x <- x[with(x, order(-abs(x$value))),]
If you're getting a lot of NA in your correlations, perhaps try using the use="complete.obs"
argument in your correlation call.
来源:https://stackoverflow.com/questions/6782070/display-correlation-tables-as-descending-list