问题
Is there standard implementation of fold (reduce, aggregate etc) for one dimensional vector in Octave? If no, is there any way to express fold without using a loop statement?
回答1:
The miscellaneous package provides the function reduce. For example,
octave:6> reduce(@(x,y)(x*y), [1:5])
ans = 120
If you look at the source code for reduce, you'll see that it is a fairly simple Octave function that is implemented with a for loop, so it won't be more efficient than implementing the reduction with a for loop of your own.
来源：https://stackoverflow.com/questions/22898711/fold-function-in-octave