Calculating differences of subsequent elements of a sequence in F#

问题

I have a sequence of floats in F#, and I need to get a sequence defined of (Math.Log currentElement)/(Math.Log previousElement). Obviously it will be shorter than the original sequence by one element.

What is the most elegant way to achieve this in F#? I was thinking to use a seq{} expression with a for loop inside, but even then handling the first element in a reasonably nice way seems difficult...

回答1:

items |> Seq.pairwise |> Seq.map (fun (x, y) -> log y / log x)

回答2:

Or if you prefer:

let f (x, y) = (log y) / (log x)

let ans = s |> Seq.pairwise |> Seq.map f

来源：https://stackoverflow.com/questions/12161015/calculating-differences-of-subsequent-elements-of-a-sequence-in-f