Run exe file with Child Process NodeJS

问题

I want to open google chrome with nodejs, but I get this error (I used execFile and spawn),

code

var execFile = require('child_process').execFile,
spawn = require('child_process').spawn,

spawn('C\\Program Files\\Google\\Chrome\\Application\\chrome.exe', function (error, stdout, stderr) {
   if (error !== null) { console.log('exec error: ' + error); }
});

events.js:72
    throw er; // Unhandled 'error' event
          ^
Error: spawn ENOENT
at errnoException (child_process.js:998:11)
at Process.ChildProcess._handle.onexit (child_process.js:789:34)

回答1:

Each command is executed in a separate shell, so the first cd only affects that shell process which then terminates. If you want to run git in a particular directory, just have Node set the path for you:

exec('git status', {cwd: '/home/ubuntu/distro'}, /* ... */);

cwd (current working directory) is one of many options available for exec.refer to link

来源：https://stackoverflow.com/questions/23764429/run-exe-file-with-child-process-nodejs