How do I define a friend class from the global namespace in another namespace?

问题

In a previous Q&A (How do I define friends in global namespace within another C++ namespace?), the solution was given for making a friend function definition within a namespace that refers to a function in the global namespace.

I have the same question for classes.

class CBaseSD;

namespace cb {
class CBase
{
    friend class ::CBaseSD; // <-- this does not work!?
private:
    int m_type;
public:
    CBase(int t) : m_type(t) {};
};
}; // namespace cb

class CBaseSD
{
private:
    cb::CBase*  m_base;
public:
    CBaseSD(cb::CBase* base) : m_base(base) {};
    int* getTypePtr()
    { return &(m_base->m_type); };
};

If I put CBaseSD into a namespace, it works; e.g., friend class SD::CBaseSD; but I have not found an incantation that works for the global namespace.

I am compiling with g++ 4.1.2.

回答1:

As stated in some of the comments below the question, the code in the question appears to work with me (Linux-Ubuntu-16.04, gcc version 5.4.0), provided that the friend class was forward-declared.

In pursuit of an answer, I came across this post that both explains proper technique for making friend class of a global namespace and answers why it needs to be declared the way it does. It is a nice thread because it references the standard.

As stated earlier, the class of a global namespace must be forward declared before it can be used as a friend class to a class within a namespace.

回答2:

add the forward declaration like below

namespace {  
  // anonymous namespace declaration
  class CBaseSD;
}

then your normal

friend class CBaseSD;// no need of ::

works in CBase

来源：https://stackoverflow.com/questions/2236712/how-do-i-define-a-friend-class-from-the-global-namespace-in-another-namespace

标签

c++

namespaces

global

friend