Parse error: syntax error, unexpected '(', expecting ',' or ';' in

浪尽此生 提交于 2019-11-27 02:04:10

You can't initialize member variables to anything that is not static, and you're trying to call a function.

From the manual:

This declaration may include an initialization, but this initialization must be a constant value--that is, it must be able to be evaluated at compile time and must not depend on run-time information in order to be evaluated.

The workaround is to set your variable in the constructor:

private $random_name;
public function __construct() { 
    $this->random_name = rand(1000,9999).rand(1000,9999).rand(1000,9999).rand(1000,9999);
}

You can't do this:

private $image_dimensions = getimagesize($temp_dir);

Functions, variables, and anything else not static can't be called to set class variables.

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!