问题
I have this users collection:
{
"_id" : ObjectId("501faa18a34feb05890004f2"),
"username" : "joanarocha",
}
{
"_id" : ObjectId("501faa19a34feb05890005d3"),
"username" : "cristianarodrigues",
}
{
"_id" : ObjectId("501faa19a34feb05890006d8"),
"username" : "anarocha",
}
When I query this: db.users.find({'username': /anaro/i})
results are sorted in natural order (insertion order).
I would like to sort them in a similarity search-term order. In this case results should return by this order:
{ "_id" : ObjectId("501faa19a34feb05890006d8"), "username" : "anarocha", } { "_id" : ObjectId("501faa18a34feb05890004f2"), "username" : "joanarocha", } { "_id" : ObjectId("501faa19a34feb05890005d3"), "username" : "cristianarodrigues", }
回答1:
Unfortunately, MongoDB doesn't support full text search ranking by default.
First of all, you will need a algorithm to calculate the similarity between strings. See following links:
String similarity algorithims?
String similarity -> Levenshtein distance
Then you need to write a javascript function using the algorithm to compare two strings to pass it in your query. See the following link to see how to achieve that:
Mongo complex sorting?
来源:https://stackoverflow.com/questions/12005490/sort-results-by-search-term-similarity