问题
I am trying to use a trait that has a function that takes a closure as argument, and then use it on a trait object.
trait A {
fn f<P>(&self, p: P) where P: Fn() -> ();
}
struct B {
a: Box<A>
}
impl B {
fn c(&self) {
self.a.f(|| {});
}
}
This snippet generates the following error:
the trait `A` is not implemented for the type `A` [E0277]
The version of rustc
is rustc 1.0.0-beta.3 (5241bf9c3 2015-04-25) (built 2015-04-25)
.
回答1:
The problem is that method f
is not object-safe because it is generic, and hence it can't be called on a trait object. You will have to force its users to pass boxed closure:
trait A {
fn f(&self, p: Box<Fn() -> ()>);
}
I wonder why Rust allows Box<A>
in the first place, I would expect an error there. And this particular error is really misleading. I would file a bug about this.
Alternatively, you can discard trait objects in favor of regular bounded generics, though it is not always possible.
来源:https://stackoverflow.com/questions/30055356/the-trait-a-is-not-implemented-for-the-type-a