问题
I have microcontroler that I am working with. When debugging it is necessary to call a function from that is hard coded in ROM. Technical Reference shows how to do this:
# define Device_cal (void(*)(void))0x3D7C80
and calling procedure looks like this:
(*Device_cal)()
I can't understand what actually happens here, so my question is: How does it work?
回答1:
The #define causes (*Device_cal)() to be expanded into this immediately before compiling:
(*(void(*)(void))0x3D7C80)()
The void(*)(void) is a declaration for a function pointer that takes void and returns void types. The (*()) represents a cast for the next token in the expression (0x3D7C80). Thus this asks to treat the data at location 0x3D7C80 as a function. The final () calls the function with no arguments.
回答2:
void (*) (void) is a type. It's a pointer to a function that takes no parameter and returns void.
(void(*)(void)) 0x3D7C80 casts the 0x3D7C80 integer to this function pointer.
(*Device_cal)() calls the function.
(Device_cal)() would do the exactly the same.
The parentheses around *Device_cal and Device_cal are required because otherwise the cast to the integer would not have the higher precedence.
回答3:
well, you "define" a pointer to function, and call it.
void(*)(void) mean a pointer to function, that gets no arguments, and return void.
If you cast 0x3D7C80 to that type, and call it, you basically call the function that its address is 0x3D7C80.
回答4:
This is not an answer (that has already been done satisfactorily), but some advice:
I would suggest the following method instead:
typedef void (*tVOID_ROMFUNCTION_VOID)( void ) ;
tVOID_ROMFUNCTION_VOID Device_cal = (tVOID_ROMFUNCTION_VOID)0x3D7C80 ;
Device_cal() ;
That way you can create any number of global function pointers on initialisation while the calls look like normal statically linked functions. And you avoid confusing pre-processor macros voodoo at the same time.
By creating different function-pointer types with different signatures, the compiler will be able to perform some parameter type checking for you too.
回答5:
The symbol is pasted in which creates a temporary (un named ) pointer to a function at a fixed memory location and then calls it via dereferencing.
来源：https://stackoverflow.com/questions/8919343/pointer-to-function-in-rom