Why are mutable values in Python Enums the same object?

问题

While experimenting with different value types for Enum members, I discovered some odd behavior when the values are mutable.

If I define the values of an Enum as different lists, the members still behave similarly to when the Enum values are typical immutable types like str or int, even though I can change the values of the members in place so that the values of the two Enum members are the same:

>>> class Color(enum.Enum):
        black = [1,2]
        blue = [1,2,3]  

>>> Color.blue is Color.black
False
>>> Color.black == Color.blue
False
>>> Color.black.value.append(3)
>>> Color.black
<Color.black: [1, 2, 3]>
>>> Color.blue
<Color.blue: [1, 2, 3]>
>>> Color.blue == Color.black
False
>>> Color.black.value == Color.blue.value
True

However, if I define the values to be identical lists, each member's value seems to be the same object, and thus any mutation of one member's value affects all members:

>>> class Color(enum.Enum):
        black = [1,2,3]
        blue = [1,2,3]

>>> Color.blue is Color.black
True
>>> Color.black == Color.blue
True
>>> Color.black.value.append(4)
>>> Color.black
<Color.black: [1, 2, 3, 4]>
>>> Color.blue
<Color.black: [1, 2, 3, 4]>
>>> Color.blue == Color.black
True

Why does Enum behave this way? Is it the intended behavior or is it a bug?

NOTE: I'm not planning on actually using Enums this way, I was simply experimenting with using non-standard values for Enum members

回答1:

From the docs:

Given two members A and B with the same value (and A defined first), B is an alias to A. By-value lookup of the value of A and B will return A. By-name lookup of B will also return A:
>>> class Shape(Enum):
...     square = 2
...     diamond = 1
...     circle = 3
...     alias_for_square = 2
...
>>> Shape.square
<Shape.square: 2>
>>> Shape.alias_for_square
<Shape.square: 2>
>>> Shape(2)
<Shape.square: 2>

This operates by equality, even when the values are mutable. Since you defined equal values for black and blue, with black first, blue is an alias for black.

回答2:

To complement @user2357112's answer, take a look in EnumMeta, the metaclass for all Enum classes; it gets a peek at every class definition that has its type and gets a change to alter it.

Specifically, it takes care to re-assign members with the same value in its __new__ method via simple assignment:

    # If another member with the same value was already defined, the
    # new member becomes an alias to the existing one.
    for name, canonical_member in enum_class._member_map_.items():
        if canonical_member._value_ == enum_member._value_:
            enum_member = canonical_member
            break

I didn't opt to check the docs and instead looked in the source. Lesson to take: Always check the docs, and if ExplanationNotFound is raised; check the source :-)

回答3:

From the Python documentation for Enums:

By default, enumerations allow multiple names as aliases for the same value. When this behavior isn’t desired, the following decorator can be used to ensure each value is used only once in the enumeration....

This means that blue is an alias for black. When either one changes, the other must as well.

You can however, force Python to make each enum value unique, by using the enum.unique decorator. Also from the docs:

>>> from enum import Enum, unique
>>> @unique
 ... class Mistake(Enum):
 ...     one = 1
 ...     two = 2
 ...     three = 3
 ...     four = 3
 ...
 Traceback (most recent call last):
 ...
 ValueError: duplicate values found in <enum 'Mistake'>: four -> three

回答4:

Python 3 Enum class doesn't enforce uniqueness unless you specifically tell it to via the unique decorator

See also duplicate values. since blue is identical to black, it just becomes an alias for black.

来源：https://stackoverflow.com/questions/40641213/why-are-mutable-values-in-python-enums-the-same-object

标签

python

python-3.x

enums

identity