问题
Whe I run it fgets() is simply ignored and scanf() doesn't input data to structure.
My code:
#include"stdio.h"
#include"stdlib.h"
typedef struct {
char nazv[50];
int numr;
int date[3];
int time[2];
} train;
void input(train*rasp,int n);
void print(train*rasp,int n);
void output(train*rasp, int n, int*date, int*time);
main() {
int n;
int t[2];
int d[3];
printf("How much? ");
scanf("%d",&n);
train* rasp=(train*)malloc(n*sizeof(train));
input(rasp,n);
printf("Enter date: ");
for (int date=0;date<3;date++) {
scanf("%d",&d[date]);
}
printf("Enter time: ");
for (int time=0;time<2;time++) {
scanf("%d",&t[time]);
}
for (int i=0;i<n;i++)
print(rasp,n);
output(rasp,n,d,t);
free(rasp);
return 0;
}
void input(train*rasp,int n) {
for (int i=0;i<n;i++) {
printf("Train #%d\n",i+1);
printf("Enter train's name: ");
fgets(rasp[i].nazv,50,stdin);
printf("Enter train's number: ");
scanf("%d",&rasp[i].numr);
printf("Enter date: ");
for (int d=0;d<3;d++) {
scanf("%d",&rasp[i].date[d]);
}
printf("Enter time: ");
for (int t=0;t<2;t++) {
scanf("%d",&rasp[i].time[t]);
}
}
printf("\nOK.");
}
void print(train*rasp,int n) {
printf("Name: ");
printf("%s",rasp[n].nazv);
printf("\nNumber: %d",rasp[n].numr);
printf("\nDate: %d.%d.%d", rasp[n].date[0],rasp[n].date[1],rasp[n].date[2]);
printf("\nTime: %d:%d\n", rasp[n].time[0],rasp[n].time);
}
void output(train*rasp,int n,int*date,int*time) {
for (int i=0;i<n;i++) {
if (rasp[n].date[2]<date[2])
continue;
if (rasp[n].date[2]>date[2]) {
print(rasp,n);
} else {
if (rasp[n].date[1]<date[1])
continue;
if (rasp[n].date[1]>date[1]) {
print(rasp,n);
} else {
if (rasp[n].date[0]<date[0])
continue;
if (rasp[n].date[0]>date[0]) {
print(rasp,n);
} else {
if (rasp[n].time[0]<time[0])
continue;
if (rasp[n].time[0]>time[0]) {
print(rasp,n);
} else {
if (rasp[n].time[1]<=time[1])
continue;
print(rasp,n);
}
}
}
}
}
}
input() function should put trains into to database. output() function should only print trains from database with a date later than the one user supplied before.
回答1:
scanf("%d",&n);
scanf
leaves the newline that sent the input to the programme in the input buffer.
train* rasp=(train*)malloc(n*sizeof(train));
input(rasp,n);
void input(train*rasp,int n) {
for (int i=0;i<n;i++) {
printf("Train #%d\n",i+1);
printf("Enter train's name: ");
fgets(rasp[i].nazv,50,stdin);
fgets
finds a newline as the first character in the input buffer and doesn't look further, leaving the train's name in the input buffer.
printf("Enter train's number: ");
scanf("%d",&rasp[i].numr);
Which scanf
fails to convert into an int
.
Mixing scanf
and fgets
for user input is error-prone becaus of the different newline-behaviour. Unless you clear the input buffer between a scanf
and a following fgets
, the fgets
most often will only get the newline left over form the scanf
(there are a few scanf
formats that consume the newline).
You can clear the buffer
void clear_input_buffer(void) {
int c;
while((c = getchar()) != EOF && c != '\n');
if (c == EOF) {
// input stream broken, what now?
exit(EXIT_FAILURE);
}
}
or use fgets
for all input and use sscanf
(and strtol
and friends) to parse the input.
来源:https://stackoverflow.com/questions/14303008/when-i-run-my-program-fgets-is-ignored-and-scanf-doesnt-input-data-to-stru