Converting a string to uint8_t array in C++

问题

I want an std::string object (such as a name) to a uint8_t array in C++. The function reinterpret_cast<const uint8_t*> rejects my string. And since I'm coding using NS-3, some warnings are being interpreted as errors.

回答1:

If you want a pointer to the string's data:

reinterpret_cast<const uint8_t*>(&myString[0])

If you want a copy of the string's data:

std::vector<uint8_t> myVector(myString.begin(), myString.end());
uint8_t *p = &myVector[0];

回答2:

String objects have a .c_str() member function that returns a const char*. This pointer can be cast to a const uint8_t*:

std::string name("sth");

const uint8_t* p = reinterpret_cast<const uint8_t*>(name.c_str());

Note that this pointer will only be valid as long as the original string object isn't modified or destroyed.

来源：https://stackoverflow.com/questions/7664529/converting-a-string-to-uint8-t-array-in-c