Dismiss PopupWindow on touch outside popup, without using deprecated constructor

问题

I have a PopupWindow and I wanted it to dismiss when the user touches outside, so I looked into and found out that I had to use popup.setBackgroundDrawable(new BitmapDrawable());. The problem is that the constructor new BitmpaDrawable() is deprecated. I Would like to find a solution without using it.

Anybody knows how to solve this?

Thanks!

                final PopupWindow popup = new PopupWindow(sortByView,
                                          ViewGroup.LayoutParams.WRAP_CONTENT,
                                          ViewGroup.LayoutParams.WRAP_CONTENT,            
                                          true);
                popup.setBackgroundDrawable(new BitmapDrawable());
                popup.setOutsideTouchable(true);
                popup.showAsDropDown(v);

回答1:

What I had to do to get it to work:

popup.setBackgroundDrawable(new ColorDrawable(ContextCompat.getColor(context, android.R.color.transparent)));
popup.setOutsideTouchable(true);

回答2:

Hmm setBackgroundDrawable don't dissmiss popup window. I think that default behavior of popup window is to dismiss on touching outside but you may add onDismiss listener like that

popup.setOnDismissListener(new PopupWindow.OnDismissListener() {

    @Override
    public void onDismiss() {
        popup.dismiss();
        // end may TODO anything else                   
    }
});

回答3:

You could try.

popup.setBackgroundDrawable(new BitmapDrawable(getResources(),
            ""));

来源：https://stackoverflow.com/questions/19178069/dismiss-popupwindow-on-touch-outside-popup-without-using-deprecated-constructor