How to pass two anonymous functions as arguments in CoffeScript?

99封情书 提交于 2019-11-27 01:00:26

Put parentheses around the anonymous functions.

I think the problem lies with using single line comments //. Single-line comments enclosed in /* .. */ seem to work fine. Here's an equivalent example with something other than a comment.

$('element').hover(
  -> console.log("first")
  -> console.log("second")
)

Or with comments using /* .. */.

$('element').hover(
  -> /* first */
  -> /* second */
)

You can try these examples under the Try CoffeeScript tab. CoffeeScript adds a return statement to return the last expression of the function. If you wanted bare-bones functions which do nothing and don't contain a return at the end, try:

$('element').hover(
  () ->
  () ->
)
// $('element').hover(function() {}, function() {});

Another way is to use backslash after the caller function, the comma should be indented correctly.

$('element').hover \
  -> # do stuff on mouseover
  ,
  -> # do stuff on mouseout

Without parenthesis or backslash:

f ->
  0
, ->
  1

Output on 1.7.1:

f(function() {
  return 0;
}, function() {
  return 1;
});
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