问题
I am trying to understand to what kind of cypher "data structure" certain identifiers or expressions correspond to, depending on how and where they are used. Below I list examples I encountered. Please tell me if I got it right (in the comments) or if I am missing something.
MATCH (a:MYTYPE { label:'l_a' })
// a corresponds to a collection of nodes
MATCH (b:MYTYPE { label:'l_b' })
// so does b
MATCH p=(a)-[sp1:CF*]->(b)-[sp12:CF]->(c)
// p corresponds to a collection of paths
// a and b correspond to a collection of nodes
// (or does the previous MATCH of a and b change something?)
// sp1 corresponds to a collection of collections of relationships
// sp12 corresponds to a collection of relationships
// c corresponds to a collection of nodes
WHERE ( p = ... )
// Here, the p corresponds to a path, i.e. there must be a path or (I don't know) on the right side of the =
WHERE ( a = ... )
// a corresponds to a node, i.e. there must be a node on the right side of the =
WHERE ( sp1 = ... )
// sp1 corresponds to a collection of nodes, i.e. there must be a collection of relationships on the right side
//BONUS:
WHERE ( (e)-[sp2:CF*]->(f) ) = ...
// there must be a collection of collections of paths on the right side of the =
回答1:
I think the easiest way to answer all these questions is by passing identifiers to functions that will throw an error telling you what it expected and what it actually received. I think you should also be careful about how you use the word collection, as it is not correct.
Nodes, Relationships, Paths
MATCH (n) RETURN n;
n
is a Node
.
MATCH ()-[r]-() RETURN r;
r
is a Relationship
.
MATCH p = ()-[]-()
p
is a Path
.
Collections
MATCH (n) WITH COLLECT(n) AS c RETURN c;
c
is a Collection<Node>
.
MATCH ()-[r]-() WITH COLLECT(r) AS c RETURN c;
c
is a Collection<Relationship>
.
MATCH p = ()-[]-() WITH COLLECT(p) AS c RETURN c;
c
is a Collection<Path>
.
Variable Length Paths
MATCH p = ()-[r*..2]-() RETURN p, r;
p
is a Path
.
r
is a Collection<Relationship>
.
And to refer to your specific example:
MATCH p = (a)-[sp1:CF*]->(b)-[sp12:CF]->(c)
p
is a Path
.
a
is a Node
.
sp1
is a Collection<Relationship>
.
b
is a Node
.
sp12
is a Relationship
.
c
is a Node
.
And I'm not sure what you're asking about the WHERE
clauses. Perhaps you can clarify with an edit to your question.
来源:https://stackoverflow.com/questions/33655824/trying-to-understand-identifiers-and-collections-in-match-and-where