问题
Just getting into C++. I'm getting constantly thrown off track when I see the symbol for multiply (*) being used to denote the dereferencing of a variable
for example:
unsigned char * pixels = vidgrabber.getPixels();
Does this throw other people off? What's the tip for getting my head around this?
Thank you.
p.s. I have another reasonably simple question, that didn't get answered :( here: beginner question: add/subtract to value rather than just be that value pretty please! and thanks for your time!
回答1:
C, and by inheritance C++, are swamped with operators and are inherently context-sensitive. You will have to get used to it:
If * appears before the name of a variable that is being declared (or defined), it's a type modifier and makes that variable a pointer.
If it is a unary prefix operator for a variable that is part of an expression, it's dereferencing (or whatever it's been overloaded to).
If it is a binary infix operator for two variables that are part of an expression, it's multiplication (or whatever it's been overloaded to).
(From this you can see that the * in your unsigned char * pixel isn't a dereferencing unary prefix, but a type modifier.)
Note that & pretty much resembles *, only it's meaning is different: it makes a variable a reference, is the address-of operator, or the binary AND.
回答2:
One recommendation when writing your own code is to "cuddle" the * when using as a pointer/deref:
unsigned char *pixels = ...
if (*pixels == ...)
and to space the * when using as a multiply:
int y = x * 7;
There are other clues you can use (such as the fact that pointer deref is a unary operator while multiple is a binary operator).
回答3:
The answer is: practice. Every new programming language will look funny to some extent, some funnier than others. Learn to use it and it will become natural.
回答4:
You can distinguish the dereference operator from the multiplication operaotr by the fact that, usually, a multiplicator operator doesn't have a type name on his left.
回答5:
Contrived Example
You wrote about dereferencing in C. Can you tell the result from just looking at it? ==>
int v[] = {5,6}, w[] = {7,8};
int m[][2] = { {1,2}, {3,4} };
int result = * v * * * m * * w;
Regards
rbo
回答6:
The same way English speakers get around the fact that the same word can have different meanings depending on the context. Once you are somewhat immersed in the context, it will usually be obvious what the operator is doing.
回答7:
An important thing to note about C compared with other languages is that in when multiple declarations are combined in one statement, the asterisk applies to individual items, not the set as a whole. For example:
int* foo,bar;
creates an int-pointer called foo, and an int called bar. I always peg the asterisk to the variable, and I avoid mixing pointers and non-pointers in one statement thus:
int *foo; int *ptr1,*ptr2,*ptr3; int bar,boz,baz;
It's also important to note that storage-class qualifiers like 'const' and 'volatile' may not always bind as one would expect. The statement
volatile int *foo;does not mean that 'foo' is a volatile, but rather that what 'foo' points to is a volatile. If foo itself is the 'volatile' thing, one must write "int * volatile foo;"
来源：https://stackoverflow.com/questions/3515219/c-beginner-question-dereference-vs-multiply