问题
Problem Statement
Given N integers, compute their average, correct to three decimal places.
Input Format The first line contains an integer N. This is followed by N integers, each on a new line.
Output Format Display the average of the N integers, rounded off to three decimal places.
Input Constraints
1 <= N <= 500
-10000 <= x <= 10000 (x refers to elements of the list of integers for which the average is to be computed)
Sample Input
4
1
2
9
8
Sample Output
5.000
explaination
The '4' in the first line indicates that there are four integers whose average is to be computed. The average = (1 + 2 + 9 + 8)/4 = 20/4 = 5.000 (correct to three decimal places) Please include the zeroes even if they are redundant (eg. 0.000 instead of 0).
回答1:
You can use this awk command:
awk 'NR==1{n=$1;next} {s+=$1} END{printf "%.3f\n", s/n}' file
5.000
来源：https://stackoverflow.com/questions/27653995/compute-average-in-bash