how to post a like or delete an instagram like using instagram api?

问题

hi all could any one tell me how i can post a like and delete an instagram like using api? i tried to delete a like using this code but i dont get any response from ajax call. could any one tell me what i am doing wrong here ?is this possible doing php ?how?

xxxxxxxxxxxxxxxxxx_xxxxxxxx ==> Media-Id such as: 23424343243243_2343243243

Instagram API Docs for Deleting Like

<html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js"></script>

<script type="text/javascript">
function deleteLike() {

alert("inside function");

    var url = "https://api.instagram.com/v1/media/xxxxxxxxxxxxxxxxxx_xxxxxxxx/likes?access_token=XXXX";
    $.post(url, {
        "method": "delete",
    }, function(data) 
       {
         var ajaxResponse = data;

          alert("success"+ajaxResponse);

    })
    }

</script>
</head>
  <body onload="deleteLike();">


</html>

Edited:cross domain php curl:(but how to tell it if this is post method or delete method?"

$url = "https://api.instagram.com/v1/media/xxxxxxxxxxxxxxxxxx_xxxxxxxx/likes?access_token=XXXX";

        $api_response = get_data(''.$url);
        $record = json_decode($api_response); // JSON decode 



/* gets the data from a URL */
function get_data($url) {
    $ch = curl_init();
    $timeout = 5;
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
    $data = curl_exec($ch);
    curl_close($ch);
    return $data;
}

回答1:

EDIT: According to API specs, you need to use request of DELETE type. To do this, specify {type: "DELETE"}, not {"method": "delete"} and use $.ajax() function. See related question here: How to send a PUT/DELETE request in jQuery?

Are you sure you've got your POST request gets executed at all? It may be not running at all, please check requests in Developer Tools / Firebug / etc. And initialize your request jQuery way, don't use obtrusive JS:

$(function(){
    deleteLike();
});

The way you use success parameter you need to declare functions with more parameters: success(data, textStatus, jqXHR). This may also cause misbehavior. Please read docs here: http://api.jquery.com/jQuery.post/

I'd suggest you to use more handy .done() function:

$.post(url, { "method": "delete"})
  .done(function(data) {
    var ajaxResponse = data;
    alert("success: " + ajaxResponse);
  })
  .fail(function() {
  // check for error here
  });

You should also definitely be interested in checking .fail() result - most probably you've missed something while preparing request.

来源：https://stackoverflow.com/questions/18852810/how-to-post-a-like-or-delete-an-instagram-like-using-instagram-api

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javascript

php

jquery

ajax

instagram