leetcode1281

1 class Solution:
2     def subtractProductAndSum(self, n: int) -> int:
3         s = str(n)
4         mul,sums = 1, 0
5         for i in range(len(s)):
6             cur = int(s[i])
7             mul *= cur
8             sums += cur
9         return mul - sums

一次循环，同时记录乘积与加和。循环结束，两值再相减。

来源：https://www.cnblogs.com/asenyang/p/12005104.html