问题
I'm trying to submit a query using the postal code to my DB whenever the googlemaps viewport center changes. I know that this can be done with reverse geocoding with something like:
google.maps.event.addListener(map, 'center_changed', function(){
newCenter();
});
...
function newCenter(){
var newc = map.getCenter();
geocoder.geocode({'latLng': newc}, function(results, status){
if (status == google.maps.GeocoderStatus.OK) {
var newzip = results[0].address_components['postal_code'];
}
});
};
Of course, this code doesn't actually work. So I was wondering how I would need to change this in order to extract the postal code from the results array. Thanks
回答1:
What I've realized so far is that in most cases the ZIPCODE is always the last value inside each returned address, so, if you want to retrieve the very first zipcode (this is my case), you can use the following approach:
var address = results[0].address_components;
var zipcode = address[address.length - 1].long_name;
回答2:
You can do this pretty easily using the underscore.js libraray: http://documentcloud.github.com/underscore/#find
_.find(results[0].address_components, function (ac) { return ac.types[0] == 'postal_code' }).short_name
回答3:
Using JQuery?
var searchAddressComponents = results[0].address_components,
searchPostalCode="";
$.each(searchAddressComponents, function(){
if(this.types[0]=="postal_code"){
searchPostalCode=this.short_name;
}
});
short_name or long_name will work above
the "searchPostalCode" var will contain the postal (zip?) code IF
and only IF you get one from the Google Maps API.
Sometimes you DO NOT get a "postal_code" in return for your query.
回答4:
Alright, so I got it. The solution is a little uglier than I'd like, and I probably don't need the last for loop, but here's the code for anyone else who needs to extract crap from address_components[]. This is inside the geocoder callback function
for(i; i < results.length; i++){
for(var j=0;j < results[i].address_components.length; j++){
for(var k=0; k < results[i].address_components[j].types.length; k++){
if(results[i].address_components[j].types[k] == "postal_code"){
zipcode = results[i].address_components[j].short_name;
}
}
}
}
回答5:
This takes only two for loops. The "results" array gets updated once we found the first "type" to be "postal_code".
It then updates the original array with the newly found array set and loops again.
var i, j,
result, types;
// Loop through the Geocoder result set. Note that the results
// array will change as this loop can self iterate.
for (i = 0; i < results.length; i++) {
result = results[i];
types = result.types;
for (j = 0; j < types.length; j++) {
if (types[j] === 'postal_code') {
// If we haven't found the "long_name" property,
// then we need to take this object and iterate through
// it again by setting it to our master loops array and
// setting the index to -1
if (result.long_name === undefined) {
results = result.address_components;
i = -1;
}
// We've found it!
else {
postcode = result.long_name;
}
break;
}
}
}
回答6:
You can also use this code, this function will help to get zip on button click or onblur or keyup or keydown.
Just pass the address to this function.
use google api with valid key and sensor option removed as it doesn't required now.
function callZipAPI(addSearchZip)
{
var geocoder = new google.maps.Geocoder();
var zipCode = null;
geocoder.geocode({ 'address': addSearchZip }, function (results, status) {
if (status == google.maps.GeocoderStatus.OK) {
//var latitude = results[0].geometry.location.lat();
//var longitude = results[0].geometry.location.lng();
var addressComponent = results[0].address_components;
for (var x = 0 ; x < addressComponent.length; x++) {
var chk = addressComponent[x];
if (chk.types[0] == 'postal_code') {
zipCode = chk.long_name;
}
}
if (zipCode) {
alert(zipCode);
}
else {
alert('No result found!!');
}
} else {
alert('Enter proper address!!');
}
});
}
回答7:
I use this code to get "Postal code" and "locality", but you can use it to get any other field just changing the value of type:
JAVASCRIPT
var address = results[0].address_components;
var zipcode = '';
var locality = '';
for (var i = 0; i < address.length; i++) {
if (address[i].types.includes("postal_code")){ zipcode = address[i].short_name; }
if (address[i].types.includes("locality")){ locality = address[i].short_name; }
}
回答8:
$.each(results[0].address_components,function(index,value){
if(value.types[0] === "postal_code"){
$('#postal_code').val(value.long_name);
}
});
回答9:
places.getDetails( request_details, function(results_details, status){
// Check if the Service is OK
if (status == google.maps.places.PlacesServiceStatus.OK) {
places_postal = results_details.address_components
places_phone = results_details.formatted_phone_number
places_phone_int = results_details.international_phone_number
places_format_address = results_details.formatted_address
places_google_url = results_details.url
places_website = results_details.website
places_rating = results_details.rating
for (var i = 0; i < places_postal.length; i++ ) {
if (places_postal[i].types == "postal_code"){
console.log(places_postal[i].long_name)
}
}
}
});
This seems to work very well for me, this is with the new Google Maps API V3. If this helps anyone, write a comment, i'm writing my script as we speak... so it might change.
回答10:
In PHP I use this code. Almost in every conditions it works.
$zip = $data["results"][3]["address_components"];
$zip = $index[0]["short_name"];
回答11:
In a word, that's a lot of effort. At least with the v2 API, I could retrieve those details thusly:
var place = response.Placemark[0];
var point = new GLatLng(place.Point.coordinates[1], place.Point.coordinates[0]);
myAddress = place.AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.Thoroughfare.ThoroughfareName
myCity = place.AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.LocalityName
myState = place.AddressDetails.Country.AdministrativeArea.AdministrativeAreaName
myZipCode = place.AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.PostalCode.PostalCodeNumber
There has got to be a more elegant way to retrieve individual address_components without going through the looping jujitsu you just went through.
回答12:
This simple code works for me
for (var i = 0; i < address.length; i++) {
alert(address[i].types);
if (address[i].types == "postal_code")
$('#postalCode').val(address[i].long_name);
if (address[i].types == "")
$('#country').val(address[i].short_name);
}
回答13:
Using Jquery
- You cant be sure in which location in the address_components array the postal code is stored. Sometimes in address_components.length - 1 > pincode may not be there. This is true in "Address to latlng" geocoding.
- You can be sure that Postal code will contain a "postal_code" string. So best way is to check for that.
var postalObject = $.grep(results[0].address_components, function(n, i) {
if (n.types[0] == "postal_code") {
return n;
} else {
return null;
}
});
$scope.query.Pincode = postalObject[0].long_name;
回答14:
return $http.get('//maps.googleapis.com/maps/api/geocode/json', {
params: {
address: val,
sensor: false
}
}).then(function (response) {
var model= response.data.results.map(function (item) {
// return item.address_components[0].short_name;
var short_name;
var st= $.each(item.address_components, function (value, key) {
if (key.types[0] == "postal_code") {
short_name= key.short_name;
}
});
return short_name;
});
return model;
});
回答15:
Using JSONPath, it's easily done with one line of code:
var zip = $.results[0].address_components[?(@.types=="postal_code")].long_name;
回答16:
//autocomplete is the text box where u will get the suggestions for an address.
autocomplete.addListener('place_changed', function () {
//Place will get the selected place geocode and returns with the address
//and marker information.
var place = autocomplete.getPlace();
//To select just the zip code of complete address from marker, below loop //will help to find. Instead of y.long_name you can also use y.short_name.
var zipCode = null;
for (var x = 0 ; x < place.address_components.length; x++) {
var y = place.address_components[x];
if (y.types[0] == 'postal_code') {
zipCode = y.long_name;
}
}
});
回答17:
It seems that nowadays it's better to get it from the restful API, simply try:
https://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452&key=YOUR_KEY_HERE
Using an AJAX GET call works perfect!
Something like:
var your_api_key = "***";
var f_center_lat = 40.714224;
var f_center_lon = -73.961452;
$.ajax({ url: "https://maps.googleapis.com/maps/api/geocode/json?latlng="+f_center_lat+","+f_center_lon+"&key="+your_api_key,
method: "GET"
})
.done(function( res ) { if (debug) console.log("Ajax result:"); console.log(res);
var zipCode = null;
var addressComponent = res.results[0].address_components;
for (var x = 0 ; x < addressComponent.length; x++) {
var chk = addressComponent[x];
if (chk.types[0] == 'postal_code') {
zipCode = chk.long_name;
}
}
if (zipCode) {
//alert(zipCode);
$(current_map_form + " #postalcode").val(zipCode);
}
else {
//alert('No result found!!');
if (debug) console.log("Zip/postal code not found for this map location.")
}
})
.fail(function( jqXHR, textStatus ) {
console.log( "Request failed (get postal code via geocoder rest api). Msg: " + textStatus );
});
回答18:
Romaine M. — thanks! If you just need to find the postal code in the first returned result from Google, you can do just 2 loops:
for(var j=0;j < results[0].address_components.length; j++){
for(var k=0; k < results[0].address_components[j].types.length; k++){
if(results[0].address_components[j].types[k] == "postal_code"){
zipcode = results[0].address_components[j].long_name;
}
}
}
回答19:
I think rather than depending on the index it better checks address type key inside the component. I solved this issue by using a switch case.
var address = '';
var pin = '';
var country = '';
var state = '';
var city = '';
var streetNumber = '';
var route ='';
var place = autocomplete.getPlace();
for (var i = 0; i < place.address_components.length; i++) {
var component = place.address_components[i];
var addressType = component.types[0];
switch (addressType) {
case 'street_number':
streetNumber = component.long_name;
break;
case 'route':
route = component.short_name;
break;
case 'locality':
city = component.long_name;
break;
case 'administrative_area_level_1':
state = component.long_name;
break;
case 'postal_code':
pin = component.long_name;
break;
case 'country':
country = component.long_name;
break;
}
}
来源：https://stackoverflow.com/questions/5341023/retrieving-postal-code-with-google-maps-javascript-api-v3-reverse-geocode