问题
I have this code and I don't understand why I'm getting a NullPointerException:
public static ArrayList<String> retrieveObject(String istance,String property){
String sparqlQueryString= "PREFIX rdf: <http://www.w3.org/1999/02/22-rdf- syntax-ns#> "+
"PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#> "+
"PREFIX dbpedia: <http://dbpedia.org/resource/> "+
"PREFIX o: <http://dbpedia.org/ontology/> "+
"PREFIX dbprop: <http://dbpedia.org/property/>"+
"PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>" +
"select ?c"+
"where {<"+istance+"> "+property+" ?c.}";
ArrayList<String> array = new ArrayList<String>();
Query query = QueryFactory.create(sparqlQueryString);
QueryExecution qexec = QueryExecutionFactory.sparqlService("http://dbpedia.org/sparql", query);
ResultSet res = qexec.execSelect();
for(; res.hasNext();) {
QuerySolution soln = res.nextSolution();
for(int i=0;i<query.getProjectVars().size();i++){
array.add(soln.get(query.getProjectVars().get(i).getVarName()).asResource().toString());
}
}
return array;
}
I call the method in this way:
System.out.println(retrieveObject("http://dbpedia.org/resource/Immanuel_Kant","o:deathPlace"));
回答1:
I have Null pointer exception at this line: array.add(soln.get(query.getProjectVars().get(i).getVarName()).asResource().toString());
Break the expression apart to find the NPE - one possibility is that it isn't a URI so asResource
is wrong.
Better might be
for(String var : query.getResultVars() {
Resource r = soln.getResource(var) ;
array.add(r.getURI()) ;
}
(beware of blank nodes)
来源:https://stackoverflow.com/questions/19346744/unexpected-nullpointerexception-while-accessing-results-of-a-query