问题
I have some code in my postwwwacct script which doesn't work, it doesn't import the sql file
shell_exec("cd /home/".$opts['user']."/public_html/sbans/sql/");
$command="mysql -u ".$opts['user']." -p".$opts['pass']." ".$opts['user']."_bans < data.sql";
shell_exec($command);
However after account creation i can manually run in ssh
cd /home/jason/public_html/sbans/sql/
mysql -u jason -pmypass jason_bans < data.sql
Which then works.
What is the problem with the php code in postwwwacct?
Sorry for re-editing your edit but the file does not have php extension i manually call the php compiler by using
#!/usr/local/bin/php -q
回答1:
the problem is that shell_exec does cd and finishes so the command which would do the import with the sql is not found and failed.
try something like this :
<?php
$command="mysql -u ".$opts['user']." -p".$opts['pass']." ".$opts['user']."_bans < data.sql";
$output = shell_exec("cd /home/".$opts['user']."/public_html/sbans/sql/ && ".$command);
and if you want to see the result of your command just do
echo $output
回答2:
Off the top of my head, are you sure the file data.sql is in all the different user's sql folders? You could also create a seperate bash script and call it in your script, that worked for me before, you just pass in the parameters with something like this:
$t = shell_exec("path/command.sh '$opts['user']' '$opts['pass']' 2>&1");
echo $t
and in the bash script start off like this to get the variables: #!/bin/bash
#Get variables needed
user=$1
pass=$2
You can then proceed to use the variables as any normal bash variables, and if it is still not working for you becouse of the 2>&1 at the end of your shell_exec command you'll be able to debug it alot easier.
Good luck!
来源：https://stackoverflow.com/questions/12072479/php-script-to-import-file-in-mysql