How to keep a color in a fill() the same after mousePressed?

问题

What would be the easiest and simplest way to keep the fill() the same after clicking (that's when it changes) and then unclicking, and leaving hover?

In this project, I simply made a grid. When the mouse hovers over a specific rect (at x,y) it changes color based on the state it is in. fill(50) is the default, fill(75) is when the mouse is hovering, and fill(100) is when the mouse clicks. But here when the mouse is unclicked it returns to hover fill until the mouse leaves the rectangle. Thanks.

int cols, rows;
int scl = 20;

void setup() {
size(400, 400);
int w = 400;
int h = 400;
cols = w / scl;
rows = h / scl;
}

void draw() {
background(255);

  for (int x = 0; x < cols; x++) {
    for (int y = 0; y < rows; y++) {
      int xpos = x*scl;
      int ypos = y*scl;
      stroke(55);
      if((mouseX >= xpos && mouseX <= xpos+scl) &&
        (mouseY >= ypos && mouseY <= ypos+scl)){
        fill(75);
        if (mousePressed == true){
          println("Clicked at: " + xpos + " and " + ypos);
          fill(100);
        //here is the desired location for the fill to remain constant even 
        //after unclicking and leaving hover
        }
        println("Mouse at: " + xpos + " and " + ypos);
      }else{
        fill(50);
      }

      rect(xpos, ypos, scl, scl);
    }
  }
}

回答1:

Stack Overflow isn't really designed for general "how do I do this" type questions. It's for specific "I tried X, expected Y, but got Z instead" type questions. But I'll try to help in a general sense:

You need to store the state of each cell in a data structure, and then use that data structure to draw your scene.

You could do this with a 2D array, where each cell in the array represents a cell in the grid. You could store the state of the cell, or the color directly.

回答2:

As Kevin said, you should keep the state of your application in a matrix.

boolean[][] matrix = new boolean[21][21];

When you click on a cell, toggle it

if(!matrix[xpos/scl][ypos/scl]) {
    matrix[xpos/scl][ypos/scl] = true;
} else {
    matrix[xpos/scl][ypos/scl] = false;
}

Inside this loop, check if your current position can be drawn or not

if(matrix[x][y]) {
    fill(204, 102, 0); // an orange color
    rect(xpos, ypos, scl, scl);
}

So your draw() method should look like this

void draw() {
    background(255);
    for (int x = 0; x < cols; x++) {
        for (int y = 0; y < rows; y++) {
            int xpos = x*scl;
            int ypos = y*scl;

            stroke(55);
            if((mouseX >= xpos && mouseX <= xpos+scl) &&
                    (mouseY >= ypos && mouseY <= ypos+scl)){
                fill(75);
                if (mousePressed == true){
                    println("Clicked at: " + xpos + " and " + ypos);
                    if(!matrix[xpos/scl][ypos/scl]) {
                        matrix[xpos/scl][ypos/scl] = true;
                    } else {
                        matrix[xpos/scl][ypos/scl] = false;
                    }
                    fill(100);
                    //here is the desired location for the fill to remain constant even 
                    //after unclicking and leaving hover
                }
                println("Mouse at: " + xpos + " and " + ypos);
            }else{
                fill(50);
            }
            if(matrix[x][y]) {
                fill(204, 102, 0);
                rect(xpos, ypos, scl, scl);
            }
            rect(xpos, ypos, scl, scl);
        }
    }
}

来源：https://stackoverflow.com/questions/46104309/how-to-keep-a-color-in-a-fill-the-same-after-mousepressed

标签

java

processing

fill

rect