Python - Using .format() string in a MySQL statement

问题

I'm trying to format a mysql statement with today's data, as well as 7 days back. I'm pretty sure the date is in the correct format, so I don't think that's the issue.

The error report is:

 Warning: (1292, "Incorrect datetime value: '{} 16:00:00' for column 'run_start_date' at row 1")
      result = self._query(query)
    Traceback (most recent call last):
         AttributeError: 'int' object has no attribute 'format'

e.g.

today = DT.date.today()
week_ago = today - DT.timedelta(days=7)
print(today.strftime('%Y-%m-%d'))
print(week_ago.strftime('%Y-%m-%d'))

cursor.execute(SELECT * FROM db WHERE run_start_date BETWEEN '{} 16:00:00' AND '{} 16:00:00'format(week_ago, today)

回答1:

Using prepared statements (safe way):

qry = """
    SELECT *
    FROM db
    WHERE run_start_date BETWEEN '%s 16:00:00' AND '%s 16:00:00'
""" # 

today = DT.date.today()
week_ago = today - DT.timedelta(days=7)
today = str(today.strftime('%Y-%m-%d'))  # Convert to string
week_ago = str(week_ago.strftime('%Y-%m-%d'))  # Convert to string

cursor.execute(qry, [today, week_ago])

Using .format() which leaves you at risk for sql injections (if you pass user input to .format() e.g.)

qry = """
    SELECT *
    FROM db
    WHERE run_start_date BETWEEN '{today} 16:00:00' AND '{week_ago} 16:00:00'
""" # Use named placeholders, nicer to read, prevents you having to repeat variables multiple time when calling .format()

today = DT.date.today()
week_ago = today - DT.timedelta(days=7)
today = str(today.strftime('%Y-%m-%d'))  # Convert to string
week_ago = str(week_ago.strftime('%Y-%m-%d'))  # Convert to string

qry = qry.format(today=today, week_ago=week_ago)
cursor.execute(qry)

来源：https://stackoverflow.com/questions/47318901/python-using-format-string-in-a-mysql-statement

标签

python

mysql

string.format