How to disable TouchUpInside Action outside the boundary of button

问题

This is my Xib. I just dragged a UIButton and changed its background color.

I created a semi circle layer using this code

    let circlePath = UIBezierPath.init(arcCenter: CGPointMake(mybutton.bounds.size.width / 4, 0), radius: mybutton.bounds.size.height, startAngle: 0.0, endAngle: CGFloat(M_PI), clockwise: true)
    let circleShape = CAShapeLayer()
    circleShape.path = circlePath.CGPath
    mybutton.layer.mask = circleShape

and this is my output.

Its perfect as I want it. But the problem is that this button is clickable outside its rounded area(as per actuall shape of button). I want it to be clickable only as rounded shape.

How can I achieve this ? Thanks.

回答1:

Create action of signature

- (IBAction)buttonPressed:(id)sender forEvent:(UIEvent*)event{
//your code
}

for your button

Find out touch location using this answer UIButton TouchUpInside Touch Location

Check if that location is contained in your CGPath using

- (IBAction)buttonPressed:(id)sender forEvent:(UIEvent*)event{
  //find location point using above answer link
  if([button.layer.mask containsPoint: location])
  {
   //proceed with the code
  }
}

it returns a bool if it contains point.

i.e if it contains point you can proceed otherwise you can return.

Hope it helps :)

来源：https://stackoverflow.com/questions/37657307/how-to-disable-touchupinside-action-outside-the-boundary-of-button

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ios