问题
I have a simple equation I'm trying to solve
num1=-2
num2=-3
x+num2=num1
x+-3=-2
x=1
How can I do this in octave. In matlab I can do y = solve('x-3 = -2') but this doesn't work in octave 3.8.1 which is the version I'm using. How can I get octave to solve these types of equations?
I'm interested in the numeric value for a solution.
回答1:
I'm assuming that the equation in your question is an example. If you're interested in a numeric solution, there is often no need to use symbolic math. In Octave (or Matlab), you can can use fzero to find a real root/zero of a nonlinear equation in terms of a single-variable free variable. For your simple linear example, using an anonymous function to represent your equation:
num1 = -2;
num2 = -3;
f = @(x)x+num2-num1;
x0 = 0; % Initial guess for x
x = fzero(f,x0)
If an equation has multiple roots/zeros you'll need to try different initial guesses in the vicinity of each zero to find the exact value.
Octave also has a version of Matlab's fsolve to solve systems of nonlinear equations in multiple variables. If your equations are linear (e.g., A*x = b), you should look at linsolve.
回答2:
Type in these commands:
syms x
solve(x-3==2)
And you should get the following:
ans = (sym) 5
This was checked using an online version of Octave
回答3:
See this discussion here: http://octave.1599824.n4.nabble.com/Newbie-question-on-solving-simple-equations-td1635574.html
Octave isn't really made to do those types of problems, however you might get away with using Fsolve. I would've put this in a comment as it isn't exactly a solution, but I don't have enough rep! sorry
来源：https://stackoverflow.com/questions/25692490/solving-equation-using-octave