问题
I'm trying to collect information from a textfile which contains names of organisations (without spaces) and floating integers. I want to store this information in an array structure.
The problem I'm having so far is collecting the information. Here is a sample of the textfile:
CBA 12.3 4.5 7.5 2.9 4.1
TLS 3.9 1 8.6 12.8 4.9
I can have up to 128 different numbers for each organisation, and up to 200 organisations in the textfile.
This is what my structure looks like so far:
struct callCentre
{
char name[256];
float data[20];
};
My main:
int main()
{
callCentre aCentre[10];
getdata(aCentre);
calcdata(aCentre);
printdata(aCentre);
return 0;
}
And the getdata function:
void getdata(callCentre aCentre[])
{
ifstream ins;
char dataset[20];
cout << "Enter the name of the data file: ";
cin >> dataset;
ins.open(dataset);
if(ins.good())
{
while(ins.good())
{
ins >> aCentre[c].name;
for(int i = 0; i < MAX; i++)
{
ins >> aCentre[c].data[i];
if(ins == '\n')
break;
}
c++;
}
}
else
{
cout << "Data files couldnt be found." << endl;
}
ins.close();
}
What I'm trying to achieve in my getdata function is this: store the organisation name first into the structure, then read each float into the data array until the program detects a newline byte. However, so far my check for the newline byte isn't working.
Assume that variables c and MAX are already defined.
How should I go about this properly?
回答1:
char byte = ins.peek();
Or
if(ins.peek() == '\n') break;
(Edit): You'll want to also check for an eof after your peek(), because some files may not have a ending newline.
I'd like to point out that you might want to consider using a vector<callCentre>
instead of a static array. If your input file length exceeds the capacity of the array, you'll walk all over the stack.
回答2:
The >> operator treats whitespace as a delimiter, and that includes newlines, so it just eats those and you never see them.
回答3:
You need to read lines and then chop the lines up. The following bit of hackery illustrates the basic idea:
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
int main() {
string line;
while( getline( cin, line ) ) {
istringstream is( line );
string cs;
is >> cs;
double vals[10];
int i = 0;
while( is >> vals[i] ) {
i++;
}
cout << "CS: " << cs;
for ( int j = 0; j < i; j++ ) {
cout << " " << vals[j];
}
cout << endl;
}
}
回答4:
I would read the file, one line after another and parse each line individually for the values:
std::string line;
while (std::getline(ins, line)) {
std::istringstream sline(line);
sline >> aCentre[c].name;
int i = 0;
while (sline >> aCentre[c].data[i])
i++;
c++;
}
来源:https://stackoverflow.com/questions/640983/detect-newline-byte-from-filestream