How to convert __u32 to __be32 in Linux Kernel

问题

I've a variable

__be32 x;

I've a function

__u32 foo(void){
      __u32 a;
      return a;
}

I need to store the return of foo in variable x.

x=htonl(foo());

Is it correct? I've a confusion that what are the return types of ntohl() and htonl(). Are they opposite of each other?

To check the output, I need to recompile the kernel and I don't want to trouble my system with any errors. So I'm asking here.

回答1:

You can use the macros defined in kernel.h:

http://www.bruceblinn.com/linuxinfo/ByteOrder.html

The following macros return the value after it has been converted. Note: the linux/kernel.h header file is the header file that should be included in the source files where these macros are used, but it is not the header file where the macros are actually defined.

#include <linux/kernel.h>
__u16   le16_to_cpu(const __le16);
__u32   le32_to_cpu(const __le32);
__u64   le64_to_cpu(const __le64);

__le16  cpu_to_le16(const __u16);
__le32  cpu_to_le32(const __u32);
__le64  cpu_to_le64(const __u64);

__u16   be16_to_cpu(const __be16);
__u32   be32_to_cpu(const __be32);
__u64   be64_to_cpu(const __be64);

__be16  cpu_to_be16(const __u16);
__be32  cpu_to_be32(const __u32);
__be64  cpu_to_be64(const __u64);

来源：https://stackoverflow.com/questions/21932790/how-to-convert-u32-to-be32-in-linux-kernel