Dynamically Linking Python Extension (.pyd) to Another Extension

问题

Python Extension modules are just dynamic libraries, so I assume it's possible to dynamically link a Python extension to another. The problem is on Windows Python Extensions are are given the .pyd extension instead of .dll, so I can't get distutils to link to them when I run the setup script. (I don't think this is a problem on UNIX because Python extensions use the .so file extension.)

Assume I have an extension bar.pyd which needs to link to foo.pyd. Basically, what I did in the setup script was:

from distutils.core import setup, Extension

foo = Extension("foo", sources=["foo.c"])
bar = Extension("bar", libraries=["foo"], sources=["bar.c"])
setup(ext_modules=[foo, bar])

So far this isn't working. Is this even possible? I assume it is, but I haven't been able to find anything online. I'm using MinGW on Windows, but I would like this to work with different MSVC++ and on other systems as well.

Edit: Previously, I solved this problem by passing the object file (foo.o) created when foo was compiled to the extra_objects option in the extension (this would only work if I defined prototypes of all foo symbols in bar):

bar = Extension("bar", sources=["bar.c"], extra_objects=["build/.../foo.o"]

This didn't seem to be the right solution, but it worked. I don't understand dynamic linking that well, so this may be the right way to do it. It feels very wrong, though.

Then, I tried passing some explicit arguments to gcc to make it compile an import library:

foo = Extension("foo", sources=["foo.c"], extra_compile_args=["-Wl,--out-implib,foo.lib,--export-all-symbols"])

And then I linked bar to the new import library:

bar = Extension("bar", libraries=["foo"], sources=["bar.c"])

This compiled without complaint, but there were some issues with some of the symbols (specifically, I had a few global PyTypeObjects in foo that seemed to be redefined in bar. I need the PyTypeObjects in both modules refer to the same definition.).

Edit 2: So, I singled out the problem. Function symbols were exporting correctly after I built and linked against the import libraries, but the PyTypeObjects were getting redeclared. Assume there was a PyTypeOject Foo_Type in foo. I declared it in foo.h, which was included in both foo.c and bar.c:

PyTypeObject Foo_Type;

I took that out, and put this near the top of foo.c:

PyTypeObject __declspec(dllexport) Foo_Type;

and this near the top of bar.c:

PyTypeObject __declspec(dllimport) Foo_Type;

That fixed the problem. I could then use Foo_Type in both foo and bar and it referred to the same definition of Foo_Type. The problem is, this isn't going to work on non-Windows systems. I assume if I just take the __declspecs out, it'll work fine on other systems.

回答1:

If you're using the normal Python import mechanisms then there's no need to link against the other extension. If you're calling functions within the other extension, presumably because you have gotten a hold on the header file, then you'll need to generate an import lib from the DLL before you can link against it.

回答2:

from distutils.core import Extension as cExtension
from pyd.support import setup, Extension

module1 = Extension("x", sources = ['xclass.c'])
module2 = Extension("y", sources = ['hello.d'], build_deimos=True)

setup(
    name = "x",
    version = '1.0',
    description = "eat a taco",
    ext_modules = [
        module1,
        module2
    ]
);

from : http://pyd.readthedocs.io/en/latest/distutils.html

来源：https://stackoverflow.com/questions/3269766/dynamically-linking-python-extension-pyd-to-another-extension

标签

python

distutils

dynamic-linking