MySQL Order from a starting value

问题

On a product page I have a dropdown that lists current colour options associated to product page.

In this example, the product page SKU is 250E and it available in:

GREEN
BLACK

If the customer selects GREEN, then I want to run a MySQL command that will change the data to show GREEN values first based in the custom_order value shown below.

The start value should overide the other data items and then it should retain custom_order values. The custom_order field has letters like c1, c2 (they will always be at the bottom)

Colour Table
============
ID      COLOURID        NAME
-------------------------------------
2           5           BLACK
3           6           GREEN


Product Table
=============
ID      SKU         PICTURE URL             COLOURID            CUSTOM_ORDER        
-----------------------------------------------------------------
22      250E        cdn_hash_1.jpg          5                   1
23      250E        cdn_hash_2.jpg          5                   2
24      250E        cdn_hash_3.jpg          5                   3
225     250E        cdn_hash_4.jpg          5                   4
226     250E        cdn_hash_5.jpg          6                   5
227     250E        cdn_hash_6.jpg          6                   6
325     250E        cdn_hash_c1.jpg         -                   c1
426     250E        cdn_hash_c2.jpg         -                   c2
527     250E        cdn_hash_c3.jpg         -                   c3

SELECT * FROM products WHERE ORDER BY custom_order DESC

Now, I want to do the following:

SELECT * FROM products WHERE ORDER BY custom_order AND START VALUE = '6'

Therefore, no matter what, the c1, c2 remain intact, result would be:

22      250E        cdn_hash_5.jpg          6                   5
23      250E        cdn_hash_6.jpg          6                   6
24      250E        cdn_hash_1.jpg          5                   1
225     250E        cdn_hash_2.jpg          5                   2
226     250E        cdn_hash_3.jpg          5                   3
227     250E        cdn_hash_4.jpg          5                   4
325     250E        cdn_hash_c1.jpg         -                   c1
426     250E        cdn_hash_c2.jpg         -                   c2
527     250E        cdn_hash_c3.jpg         -                   c3

回答1:

This is the answer I was looking for. I hope I am not downvoted for this but I managed to resolve this.

Let me explain again simpler terms. MySQL ORDER BY + Start with..

MySQL:

id | name  |
------------
1  | Joe   |
2  | Craig |
3  | Shawn |
4  | Ryan  |
5  | Seth  |

PHP:

$a = mysql_query("SELECT * FROM table_name ORDER BY name DESC");

what I want to do though is, I want to start at id: 3, so it should output:

3,4,5,1,2

Solution 1

SELECT id, name
FROM table_name
ORDER BY id < 3, id

Result:

3  Shawn
4  Ryan
5  Seth
1  Joe
2  Craig

Solution 2

You can use FIELD, eg

SELECT * 
FROM products 
ORDER BY FIELD(`order`, 6) ASC

回答2:

WHERE condition should come before ORDER BY clause

SELECT * 
FROM products 
WHERE START_VALUE = '6' 
ORDER BY order

As a sidenote, ORDER is a RESERVED keyword. One way to escape it is by wrapping with backtick. eg,

SELECT * 
FROM products 
WHERE START_VALUE = '6' 
ORDER BY `order`

Another is by supplying an ALIAS

SELECT * 
FROM products p
WHERE START_VALUE = '6' 
ORDER BY p.order

but looking back at your question, you want to custom order the data right? You can use FIELD, eg

SELECT * 
FROM products 
ORDER BY FIELD(`order`, 6) ASC

回答3:

please clear your question. if you want all records, use query like below...

SELECT * FROM products WHERE ORDER BY COLOURID ASC, order DESC

来源：https://stackoverflow.com/questions/14358656/mysql-order-from-a-starting-value